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2 years ago

12

Johnny made an apple pie. He used 2/5 of a tablespoon of cinnamon and 3/10 of a tablespoon of nutmeg. How much more cinnamon tha

n nutmeg did Johnny use?

2 answers:

EleoNora [17]2 years ago

8 0

For this case, the first thing we should do is subtract the following expressions:
2/5 of a tablespoon of cinnamon.
3/10 of a tablespoon of nutmeg.
Subtracting we have:
(2/5) - (3/10)
We apply the cross product:
((2 * 10) - (3 * 5)) / (5 * 10)
Rewriting:
((20) - (15)) / (50)
(5) / (50)
1/10
Answer:
Johnny did use 1/10 more cinnamon than nutmeg

Umnica [9.8K]2 years ago

3 0

2/5=40
3/10=30
so then its 10 (Ten)

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Thomas wants to invite Madeline to a party. He has an 80% chance of bumping into her at school. Otherwise, he’ll call her on the

Alexandra [31]

Answer:

84%

Step-by-step explanation:

The probability of Thomas bumping into her at school is 80%, so the probability of not bumping into her is 100% - 80% = 20%.

If he doesn't bump into her (20% chance), he will call her, and the probability of asking her in this case is 60%, so the final probability of asking her in this case is:

$P_1 = 20\% * 60\% = 12\%$

If he bumps into her (80% chance), the probability of asking her is 90%, so the final probability of asking her in this case is:

$P_2 = 80\% * 90\% = 72\%$

To find the probability of Thomas inviting Madeline to the party, we just have to sum the probabilities we found above:

$P = P_1 + P_2$

$P = 12\% + 72\% = 84\%$

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2 years ago

In a large apartment building, 35 of the apartments have a balcony and 55 do not.

Masteriza [31]

Hello!

You first have to find the total amount of apartments

35 + 55 = 90

There are 90 apartments

Then you find the percentage of them have a balcony

You do this by taking the amount of apartments that have a balcony over the total amount of apartments

35/90 = 0.39

0.39 as a percent is 39%

The answer is 39/100 or 39%

Hope this helps!

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2 years ago

Last week f40 fifth graders went on a field trip to the science museum

Xelga [282]

8 out of 40 fifth graders went to see the lab animal presentation. This can be written as this expression:

$\frac{8}{40}$

Find the greatest common factor of 8 and 40:

Factors of 8: 1, 2, 4, 8
Factors of 40: 1, 2, 4, 5, 8, 10, 20, 40

Therefore the greatest common factor is 8. Divide both the numerator and the denominator by 8.

$\frac{8}{40} = \frac{8/8}{40/8} = \frac{1}{5}$

Therefore the fractional part is $\frac{1}{5}$ .

To get the percentage, you need to get the denominator to a value of 100.

To do so, you need to find the value to multiply both the numerator and denominator by to achieve this.

To get this value, you can divide 100 by the denominator of the fractional value.

$100 / 5 = 20$

Then you can multiply both the numerator and denominator by 20:

$\frac{1}{5} = \frac{1 * 20}{5 * 20} = \frac{20}{100}$

From here, the numerator will state the percentage:

$20\%$

Hope this helps :)

8 0

2 years ago

Read 2 more answers

If the endpoints of `bar(AB)` have the coordinates A(9, 8) and B(-1, -2), what is the midpoint of `bar(AB)`?

alina1380 [7]

To solve this problem you must apply the proccedure shown below:

1. You have the following points given in the problem above:

$A(9,8)\\ B(-1,-2)$

2. To find the midpoint, you must apply the formula that is used for calculate it. This is:

$m=(\frac{x1+x2}{2}, \frac{y1+y2}{2} )$

Where:

$x1=9\\ x2=-1\\ y1=8\\ y2=-2$

3. Now, you must substitute these values into the formula for calculate the midpoint, as following:

$m=(\frac{9+(-1)}{2} ,\frac{8+(-2)}{2} )\\ m=(4,3)$

Therefore, the answer is: $m=(4,3)$

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2 years ago

Using mathematical induction prove whether or not the following statement is true for all positive integers n, or show why it is

aniked [119]

Base case: For $n=1$ , the left side is 2 and the right is $2\cdot1^2=2$ , so the base case holds.

Induction hypothesis: Assume the statement is true for $n=k$ , that is

$2+6+10+\cdots+4k-2=2k^2$

We want to show that this implies truth for $n=k+1$ , that

$2+6+10+\cdots+4k-2+4(k+1)-2=2(k+1)^2$

The first $k$ terms on the left reduce according to the assumption above, and we can simplify the $k+1$ -th term a bit:

$\underbrace{2+6+10+\cdots+4k-2}_{2k^2}+4k+2$

$2k^2+4k+2=2(k^2+2k+1)=2(k+1)^2$

so the statement is true for all $n\in\mathbb N$ .

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3 years ago