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stellarik [79]
3 years ago
5

Some moths have a brown body and brown wings, while other moths have a white body and white wings. The brown moths often rest on

the bark of pine trees, and the white moths rest on the white bark of aspen trees.
If all the aspen trees in an area were cut down, what would be the likely result?

PLEASE ANSWE FAST!!!!!!!!!
Biology
2 answers:
FrozenT [24]3 years ago
8 0

Answer:

D(More brown moths will survive than white moths because predators will be able to spot the whie moths more easily. Over time, there will be no white moths in the area)

Explanation:

Dennis_Churaev [7]3 years ago
5 0
BROWN!!!!!!!!!!!!!!!!
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B) uranium-235

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Do cold air masses and hot air masses automatically combine?
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You are a botanist looking at the plant color in a new breed of Snapdragon. The two parent plants are Blue and Green and when yo
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Answer:

Incomplete dominance is the inheritance pattern where the dominant allele did not mask the recessive allele completely and form a mix of both alleles. Here the inheritance is the incomplete inheritance. The ratio of F2 generation is 1:2:1.

Given:

R1R1 = 42

R2R2 = 39

R1R2 = 86

Total R1 alleles = 2*42+86 = 170

Total R2 alleles = 2*39+86 = 164

Total alleles = 334

Frequency of allele R1 = 170/334 = 0.51

Frequency of allele R2 = 164 / 334 = 0.49

Expected number of each phenotype:

Total population = 167

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Green = R2R2 = 0.49 * 0.49 * 167 = 40.10

Cyan = 2*R1*R2 = 2*0.51*0.49*167 = 83.46

Phenotype     Observed(O)    Expected (E)    O-E      (O-E)2     (O-E)2/E

Blue                 42                   43.44               -1.44       2.0736     0.0477

cyan                86                   83.46                 2.54     6.4516     0.0773

green              39                    40.1                    -1.1       1.2100      0.0302

Total              167                     167                                               0.1552

Chi-square value = 0.155

Degrees of freedom = no. of phenotypes – 1

Df = 3-1 = 2

Critical value = 5.99

Chi-square value of 0.155 is less than the critical value of 5.99. So we accept the null hypothesis.

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3 years ago
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