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Nina [5.8K]
3 years ago
12

What is the difference between Input, Output, and Storage Devices?

Computers and Technology
2 answers:
Ierofanga [76]3 years ago
8 0

Answer:

Explanation:

There are three different types of peripherals: Input, used to interact with, or send data to the computer (mouse, keyboards, etc.) Output, which provides output to the user from the computer (monitors, printers, etc.) Storage, which stores data processed by the computer (hard drives, flash drives, etc.)

cluponka [151]3 years ago
5 0
There are three different types of peripherals: Input, used to interact with, or send data to the computer (mouse, keyboards, etc.) Output, which provides output to the user from the computer (monitors, printers, etc.) Storage, which stores data processed by the computer (hard drives, flash drives, etc.)
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Counting calculus students. About A university offers 3 calculus classes: Math 2A, 2B and 2C. In both parts, you are given data
OleMash [197]

Answer:

Part (a) n(A∩B∩C) = 4

Part (b) n(A∪B∪C) = 54

Explanation:

n(A) = no. of students who took Math 2A

n(B) = no. of students who took Math 2B

n(C) = no. of students who took Math 2C

n(A∩B) = no. of students who took both Math 2A and 2B

n(A∩C) = no. of students who took both Math 2A and 2C

n(B∩C) = no. of students who took both Math 2B and 2C

n(A∩B∩C) = no. of students who took all three Math 2A, 2B and 2C

n(A∪B∪C) = no. of total students in a group

∩ represents Intersection and ∪ represents Union

Part (a)

n(A∪B∪C) = n(A) + n(B) + n(C) - n(A∩B) - n(A∩C) - n(B∩C) + n(A∩B∩C)  

Where n(A∩B∩C) represents the number of students who took all three classes and n(A∪B∪C) represents the total number of students in group A

157 = 51 + 80 + 70 - 15 - 20 - 13 + n(A∩B∩C)

Re-arranging the equation to solve for n(A∩B∩C) since we want to find out those students who took all three classes

n(A∩B∩C) = 157 - 51 - 80 - 70 + 15 + 20 + 13

n(A∩B∩C) = 4

So there are 4 students in group A who took all three classes

Part (b)

n(A∪B∪C) = n(A) + n(B) + n(C) - n(A∩B) - n(A∩C) - n(B∩C) + n(A∩B∩C)

This time we are given n(A∩B∩C) students who took all three classes and want to find n(A∪B∪C) that is total number of students

n(A∪B∪C) = 28 + 28 + 25 - 11 - 9 - 10 + 3

n(A∪B∪C) = 54

So there are total 54 students in group B

8 0
3 years ago
What can I do with this? Lol
nikitadnepr [17]
Do with what? If you have a question please contact me ;)
3 0
3 years ago
You have been given two classes, a Main.java and a Coin.java. The coin class represents a coin. Any object made from it will hav
11111nata11111 [884]

Answer:

Here is the Coin class:

public class Coin {  //class names

 private int value;  // private member variable of type int of class Coin to store the value

 private String coinName;  // private member variable of type String of class Coin to store the coint name

 private double weight;      //private member variable of type double of class Coin to store the weight

  public void setValue (int v) {  //mutator method to set the value field

    value = v;  }  

     

 public void setName(String n){  //mutator method to set coinName field

    coinName = n;}  

 public void setWeight (double w) {  //mutator method to set weight field

    weight = w;  }  

 public int getValue () {  //accessor method to get the value

   return value;  }  // returns the current value

 

 public String getName () {  //accessor method to get the coin name

   return coinName;  }  //returns the current coin name

   

 public double getWeight () {   //accessor method to get the weight

   return weight;  } } //returns the current weight

 

Explanation:

Here is the Main.java

public class Main{ //class name

public static void main(String[] args) { //start of main method

Coin penny = new Coin(); //creates object of Coin class called penny

penny.setName("Penny");  //calls setName method of Coin using object penny to set the coinName to Penny

penny.setValue(1); //calls setValue method of Coin using object penny to set the coin value to 1

penny.setWeight(0.003); //calls setWeight method of Coin using object penny to set the coin weight to 0.003

   System.out.println("Coin name: " + penny.getName()); // calls getName method of Coin using penny object to get the current coin name stored in coinName field    

   System.out.println("Coin value: " + penny.getValue()); // calls getValue method of Coin using penny object to get the coin value stored in value field    

   System.out.println("Coin weight: " +penny.getWeight()); }} // calls getWeight method of Coin using penny object to get the coin weight stored in weight field    

The value of coinName is set to Penny, that of value is set to 1 and that of weight is set to 0.003 using mutator method and then the accessor methods to access these values and prinln() to display these accessed values on output screen. Hence the output of the entire program is:

Coin name: Penny                                                                                                                                Coin value: 1                                                                                                                                   Coin weight: 0.003

The screenshot of the program along with its output is attached.

3 0
3 years ago
Given the following class definition and the variable declaration:
Lorico [155]

Answer:

The answer is "Option d".

Explanation:

In the above-given code, two-class is defined that is "employee and manager", in which the first class "employee" defines two variables that are "name, id". In this name is pointer type character and id is a long type variable.

In the second class "manager" one variable "rank" and the employee object is created. In this class, the rank variable is a pointer type character, and outside this class, a reference "x" is created.

In this code, we use both class object that uses the "employee" class variable that is id to hold value in it.

7 0
3 years ago
The Magic Square is a grid with 3 rows and 3 columns with the following properties: The grid contains every number from 1 to 9.
riadik2000 [5.3K]
Umm I’m sorry but u don’t understand
8 0
3 years ago
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