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trapecia [35]
3 years ago
6

Write a program with class name Digits that prompts the user to input a positive integer and then outputs the number reversed an

d the sum of the digits. For example, if the user enters the number 3456, then your program should output 6543 and the sum as 18. Use a while loop. Hint: use the mod operator and 10 as divider to find the right most digit and to update the value of controlling expression
Computers and Technology
1 answer:
mr Goodwill [35]3 years ago
7 0

Answer:

Written in Python:

inputnum = int(input("User Input: "))

outputnum = 0

total = 0

while(inputnum>0):

     remainder = inputnum % 10

     outputnum = (outputnum * 10) + remainder

     inputnum = inputnum//10

     total = total + remainder

print("Reverse: "+str(outputnum))

print("Total: "+str(total))

Explanation:

This prompts user for input

inputnum = int(input("User Input: "))

This initializes the reverse number to 0

outputnum = 0

This initializes total to 0; i.e. sum of each digit

total = 0

The following iteration gets the reverse of user input

<em>while(inputnum>0): </em>

<em>      remainder = inputnum % 10 </em>

<em>      outputnum = (outputnum * 10) + remainder </em>

<em>      inputnum = inputnum//10 </em>

<em>      This adds each digit of user input</em>

<em>      total = total + remainder </em>

This prints the reversed number

print("Reverse: "+str(outputnum))

This prints the sum of each digit

print("Total: "+str(total))

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