Answer:
Mason has
- 16 20¢ stamps;
- 25 3¢ stamps;
- 40 49¢ stamps.
Step-by-step explanation:
Let x be the number of 20¢ stamps, then the number of 3¢ stamps is x + 9.
Mason has 56 total 49¢ and 20¢ stamps, then the number of 49¢ stamps is 56 - x.
Amounts:
- in 49¢:
cents; - in 20¢:
cents; - in 3¢:
cents.
Total amount:

- $23.55.
Hence,

Mason has
- 16 20¢ stamps;
- 25 3¢ stamps;
- 40 49¢ stamps.
2
Step-by-step explanation:
first you multiply 4x0
then you add 2
order of operations
32*10=320 Hope you like and rate
Answer: 10
Step-by-step explanation: d = √(x^²-x^₁)^2+(y^²-y^₁)^2 d = √ (-3-5)^2+ (-5-1)^2 d = √(-8)^2 + (-6)^2 d = √64+36 d = √100 d = 10