The conditions are suitable to be modelled using a binomial distribution.
p=0.43
n=15
x=5
P(x=5)
=C(15,5)*0.43^5*(1-0.43)^(15-5)
=15!/(5!(15-5)!)*0.43^5*(1-0.43)^(15-5)
=3003*0.0147008*0.003620333
=0.1598
Answer:
0.09
Step-by-step explanation:
Answer:
Step-by-step explanation:
Yes
Answer:
1/6 is the probability of rolling a 3
Answer:
sin(arccos(-4/√25)) = 0.6
Step-by-step explanation:
The expression you want to evaluate is
sin(arccos(-4/√25))
= sin(arccos(-4/5))
We place this expression into a calculator and get the result
arccos(-4/5) = 2.498 rads = 143.1°
then
sin(143.1°) = 3/5
sin(143.1°) = 0.6
sin(arccos(-4/√25)) = 0.6