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lbvjy [14]
2 years ago
9

Find the equivalent expression for x2 + 4x + 4

Mathematics
2 answers:
Vlada [557]2 years ago
4 0

Step-by-step explanation:

Add.

2x+4x=6x

6x+4=6x+4

dlinn [17]2 years ago
4 0

Answer:

6x+4=6x+4 Step-by-step explanation:

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A bin contains seven red chips, nine green chips, three yellow chips, and six blue chips. Find the probability of drawing a yell
igomit [66]

Answer:

a) 3/100

Step-by-step explanation:

There are 25 total chips

P(Yellow) = 3/25

With no replacement P(Blue) = 6/24 = 1/4

Multiply 3/25* 1/4= 3/100

3 0
3 years ago
A company establishes a fund of 120 from which it wants to pay an amount,C, to any of its 20 employees who achieve a high-perfor
Leno4ka [110]

Answer:

C=120/2=60

Step by step Explanation'

To solve this problem, we will need to apply trial-and-error calculation with the binomial distribution, even though it appears like Central Limit Theorem but it's not.

For us to know the value of C , we will look for a minimum integer such that having 'n' number of high performance level of employee has the probability below 0.01.

Determine the maximum value of C, then the maximum value that C can have is 120/n

Let us represent X as the number of employees with high performance with a binomial distribution of

P =0.02( since the percentage of chance of achieving a high performance level is 2%)

n = 20 ( number of employees who achieve a high performance level)

The probability of X= 0 can be calculated

P( X= 0) = 0.98^n

P(X=0)=0.98^20

P(X=0)=0.668

P(X=1)=0.02*20*0.98^19

P(X=1)=0.272

P(X=2)=0.02^2*20*0.98^18

P(X=2)=0.053

Summation of P( X= 0)+ P( X= 1)+P( X= 2) will give us the value of 0.993 which is greater than 0.99( 1% that the fund will be inadequate to cover all payments for high performance.)

BUT the summation of P( X= 0)+ P( X= 1) will give the value of 0.94 which doesn't exceed the 0.99 value,

Therefore, the minimum value of integer in such a way that P(X >2) is less than 0.01 have n= 2

then the maximum value that C can have is 120/n

C=120/2=60

7 0
3 years ago
Use the discriminant to determine how many real number solutions exist for the quadratic equations -4j+3j-28=0
aleksandr82 [10.1K]
<span>the correct equation is
- 4j² + 3j - 28 =0

 ax² + bx + c,
 a = -4, b=3  c =- 28.
The discriminent D = b² - 4.a.cD = 3² - 4(-4)(-28)D = -439 
If D ≥ 0 there are either 2 roots or one double if = 0)if D< 0, there are no real roots (but 2 imaginary roots)Since D < 0, then there is no real roots
 The answer there is no real roots</span>
8 0
3 years ago
Subtract 2x^2-3xy+4y^2 from 3x^2-5xy-6y^2
Marrrta [24]

Answer:

x ^2 − 2 y ^2 −8 x y

Step-by-step explanation:

4 0
2 years ago
Please help! If GDEF is a square, GE=4x+1 and DF=8x-51, find the value of x.
zepelin [54]

Answer:

x = 13

Step-by-step explanation:

1. 4x + 1 = 8x - 51

2. 4x = 8x - 52

3. -4x = -52

4. x = 13

5 0
3 years ago
Read 2 more answers
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