Answer:
2
Step-by-step explanation:
length of pipe= 30m
Inside dia. = 1.2m
Outside dia. = 1.8m
Volume of concrete= (outside dia. - inside dia.)h
V= (pi)
v= [(3.14*0.9*0.9)-(3.14*0.6*0.6)]30
v= (3.3534-1.1304)30
v=(2.233)30 = 66.690m cube
since it's volume the answer 66.690 is in cubic meters.
The approximate amount of water that remains in the tub after the 6 spherical balls are placed in the tub are 3479.12 in³.
<h3>What is the approximate amount of water that remains in the tub?</h3>
The first step is to determine the volume of the cylinder.
Volume of the tub = πr²h
Where:
- r = radius = diameter / 2 = 18/2 = 9 inches
- h = height
- π = 3.14
3.14 x 9² x 20 = 5086.8 in³
The second step is to determine the volume of the 6 balls.
Volume of a sphere= 4/3πr³
r = diameter / 2 = 8/2 = 4 inches
6 x (3.14 x 4/3 x 4³) = 1607.68 in³
Volume that remains in the tub = 5086.8 in³ - 1607.68 in³ = 3479.12 in³
To learn more about the volume of a sphere, please check: brainly.com/question/13705125
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Answer:
Step-by-step explanation:
If you are doing probability with replacement they will all be 1/6 each time.
total there is 6/6. If you draw a yellow card first it's 1/6 then replace it and draw a blue it is still 1/6. so you take those two probabilities and multiply them (1/6)*(1/6)=1/36 1*1=1 and 6*6=36.
Your answer is 1/36
Answer:
11/12
Step-by-step explanation:
(1 1/10)/(1 1/5) = 1.1/1.2 = 11/12
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You can also work this using improper fractions:
(1 1/10)/(1 1/5) = (11/10)/(6/5) = 11/10×5/6 = (11×5)/(6×10)
= (11×5)/(6×2×5) = 11/(6×2) = 11/12
