2a) if 1 ft³ weighs 150 lb==>the TOTAL VOLUME =5,000/150 =33.334 ft³
2b) 1 ft³ 1,728 in³. So the TOTAL volume in in³ =33.334 x 1728 = 57,600 in³
c) Volume =(1/3)(πR²).H but R = H then V= (1/3)(πR³).plug V (=57600)
57,600 = 1/3 (πR³) ==> R³ = (3 x 57600) / π ==> R = 38 in
d) Area x thickness = Volume ==> Area x 2 in = 57600 in then:
Are =57600/2 & Area =28,800 in²
Answer:
+6?
Step-by-step explanation:
Sorry I just don't understand what your question is...
Answer:
height of cylinder = 4/3 h
Step-by-step explanation:
The solid has a cylinder surmounted with a cone .Therefore, the volume of the solid is the sum of the cone and the cylinder.
volume of the solid = volume of cylinder + volume of cone
volume of the solid = πr²h + 1/3πr²h
let
height of the cylinder = H
recall
the height of the cone = 2h
volume of the solid = πr²h + 1/3πr²h
3(1/3πr²2h) = πr²H + 1/3πr²2h
2πr²h = πr²H + 2/3 πr²h
πr²(2h) = πr²(H + 2/3 h)
divide both sides by πr²
2h = H + 2/3 h
2h - 2/3h = H
H = 6h - 2h/3
H = 4/3 h
height of cylinder = 4/3 h
Remark
I think you want us to do both 3 and 4
Three
QR is 4 points going left from the y axis + 2 points going right from the y axis.
QR = 6 units long.
RT is 4 units above the x axis and 3 units below the x axis
RT = 7 units long
TS = 3 units. For this one you just go from T to S. The graph really helps you. You just need to count.
Problem 4
You need to find the area of the combined figure. You could do it as a trapezoid, which might be the easiest way. I'll do that first.
Area = (b1 + b2)*h/2
Givens
B1 = QR = 6
B2 = UT + TS = 6 + 3 = 9
h = RT = 7
Area
Area = (6 + 9)*7/2
Area = 15 * 7 / 2
Area = 52.5
Comment
You could break this up into a rectangle + a triangle
Find the area of QRTU and add the Area of triangle RTS
<em>Area of the rectangle </em>= L * W
L = RT = 7
W = QR = 6
Area = 7 *6 = 42
<em>Area of the triangle</em> = 1/2 * B * H
B = TS = 3
H = RT =7
Area = 1/2 * 3 * 7
Area = 1/2 * 21
Area = 10.5
Total Area = 42 + 10.5 = 52.5 Both answers agree.
The answer is D. -(4x-3)(5x-2)
