How many integers greater than 30 and less than 40 are each the product of two distinct prime factors?

Mathematics

1 answer:

shutvik [7]3 years ago

6 0

Answer:

Step-by-step explanation:

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Brownies are now on sale. Each brownie costs $0.20 less than the original price. Right now, if you buy 8 of them it will cost $1

Airida [17]

Answer: The original price of brownie was $2.1 each.

Step-by-step explanation:

since we have given that

Let the original price will be x

Number of brownie purchased = 8

According to question , each brownie costs $0.20 less than the original price.

So, it becomes

$8\times (x-0.20)=\$15.20\\\\8x-1.6=15.20\\\\8x=15.20+1.60\\\\8x=16.8\\\\x=\frac{16.8}{8}\\\\x=\$2.1$

Hence, the original price of brownie was $2.1 each.

5 0

3 years ago

If f(x)=x^2- 4 and g(x)=x^2 plus 2 x,

gregori [183]

Answer:

$\huge\boxed{(f-g)\left(-\dfrac{1}{3}\right)=-3\dfrac{1}{3}}$

Step-by-step explanation:

$\text{We have}:\\\\f(x)=x^2-4\ \text{and}\ g(x)=x^2+2x\\\\(f-g)(x)=f(x)-g(x)\\\\\text{therefore}\\\\(f-g)(x)=(x^2-4)-(x^2+2x)=x^2-4-x^2-2x\\\\=(x^2-x^2)-2x-4=-2x-4\\\\(f-g)\left(-\dfrac{1}{3}\right)\to\text{put}\ x=-\dfrac{1}{3}\ \text{to the equation of the function}\ (f-g)(x):\\\\(f-g)\left(-\dfrac{1}{3}\right)=-2\left(-\dfrac{1}{3}\right)-4=\dfrac{2}{3}-4=-3\dfrac{1}{3}$