You can factor (x^3 and 6x^2) and (-4x and -24).
So x^2(x+6) - 4(x+6)
(x^2-4)(x+6)
(x-2)(x+2)(x+6)
Answer:
30 square millimeters
Step-by-step explanation:
3 x 3 = 9
3 x 1 = 3
there are two sides with the area 9 therefore...
9 x 2 = 18
There are four sides with the area 3 therefore...
3 x 4 = 12
Therefore the suface area is
12 + 18 = 30
Answer:
b = 6i then a = -6i
b = -6i then a = 6i
Step-by-step explanation:
a+b=0
ab=36
a = -b
a(b) = 36
-b * b = 36
- b^2 = 36
b^2 = -36
Take the square root of each side
sqrt(b^2) = sqrt(-36)
b =± 6i
a = - (± 6i)
so b = 6i then a = -6i
b = -6i then a = 6i
Answer:
The probability that a household has at least one of these appliances is 0.95
Step-by-step explanation:
Percentage of households having radios P(R) = 75% = 0.75
Percentage of households having electric irons P(I) = 65% = 0.65
Percentage of households having electric toasters P(T) = 55% = 0.55
Percentage of household having iron and radio P(I∩R) = 50% = 0.5
Percentage of household having radios and toasters P(R∩T) = 40% = 0.40
Percentage of household having iron and toasters P(I∩T) = 30% = 0.30
Percentage of household having all three P(I∩R∩T) = 20% = 0.20
Probability of households having at least one of the appliance can be calculated using the rule:
P(at least one of the three) = P(R) +P(I) + P(T) - P(I∩R) - P(R∩T) - P(I∩T) + P(I∩R∩T)
P(at least one of the three)=0.75 + 0.65 + 0.55 - 0.50 - 0.40 - 0.30 + 0.20 P(at least one of the three) = 0.95
The probability that a household has at least one of these appliances is 0.95
