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Bogdan [553]
3 years ago
9

30 points math question HELP PLEASE! will give brainliest!

Mathematics
1 answer:
Zepler [3.9K]3 years ago
5 0

Answer:

F'=12.1243557 N

Step-by-step explanation:

Let the horizontal component of force he is pulling with be F' Newtons and the force applied be F Newtons.

\therefore \cos \theta = \frac{Horizontal \: Force}{Force \: applied}

\therefore \cos \theta =  \frac{F'}{F}

\therefore F'=F\cos \theta

\therefore F'=14.\cos 30\degree

\therefore F'=14.\frac{\sqrt 3}{2}

\therefore F'=7\sqrt 3

\therefore F'=12.1243557 \: N

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