Question

30 points math question HELP PLEASE! will give brainliest!

Answer 1

Answer:

F'=12.1243557 N

Step-by-step explanation:

Let the horizontal component of force he is pulling with be F' Newtons and the force applied be F Newtons.

$\therefore \cos \theta = \frac{Horizontal \: Force}{Force \: applied}$

$\therefore \cos \theta = \frac{F'}{F}$

$\therefore F'=F\cos \theta$

$\therefore F'=14.\cos 30\degree$

$\therefore F'=14.\frac{\sqrt 3}{2}$

$\therefore F'=7\sqrt 3$

$\therefore F'=12.1243557 \: N$