X= 3 and x= -3 that should be the correct answer
The difference between the sum of all eight positive integral divisors of 66 and the sum of all eight positive integral divisors of 70 is zero.
<h3>How to find the difference between the integral divisors?</h3>
First let's find the integral divisors. We can write 66 as a product of prime numbers as:
66 = 33*2 = 2*3*11
Then the integral divisors of 66 are:
2
3
11
2*3 = 6
2*11 = 22
3*11 = 33
1 (trivially)
66 (trivially)
The sum gives:
2 + 3 + 11 + 6 + 22 +33 + 1 + 66 = 144
For 70 we have:
70 = 7*10 = 2*5*7
Then the integral divisors are:
1
70
2
5
7
2*5 = 10
2*7 = 14
5*7 = 35
The sum gives:
1 + 70 + 2 +5 + 7 + 10 + 14 + 35 = 144
Then the difference between these two sums is:
144 - 144 = 0
If you want to learn more about integral divisors:
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Answer:
The value of f(x) when x=-1 is 0.5
Therefore 
Step-by-step explanation:
Given that y=f(x)=
to find the f(x) when x=-1 :
That is to find f(-1)
Put x=-1 in the given function f(x)=
Therefore
The value of f(x) when x=-1 is 0.5
Answer:
28/q
Step-by-step explanation:
4 times 7 equals 28 and then divide 28 by q
