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3 years ago

PLZ HELP!!! I will give you brainliest

Mathematics

1 answer:

Artist 52 [7]3 years ago

6 0

Answer:

141

Step-by-step explanation:

CD = | 4-(-2)| = 6

DB = |3-(-7)| = 10

area of a right triangle

A = (leg 1 x leg2)/2 = (6 x 10)/2 = 30

EB = |3-(-3)| = 6

EF = |-8-(-2)| = 6

area of a square = side^2

A = 6^2 = 36

segment G(and a point with same x coordinate of H)

|8-3| = 5

segment H(and the same point)

|-10-(-8)| = 2

A = (5x2)/2 = 5

segment I(and the same point)

|-8-6| = 14

Area of a rectangle

A = base x width

A = (5 x 14) = 70

total area = 70 + 5 + 36 + 30 = 141

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3 years ago

Can anyone help me with this?

Dmitriy789 [7]

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3 years ago

A star athlete at a local college scored a total of 649 points during the 31 basketball games she played in the 2004 regular sea

Marina CMI [18]

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Step-by-step explanation:

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5 0

3 years ago

3(a+b)=19 if a=6, then a+b=?

aniked [119]

Hello!

In a really simple way, 3 times our answer is 19. We can just divide to find it.

19/3= 6 1/3

Anyway, it might be nice to solve the equation for b. If a=6, then b has to be 1/3, but let's check.

18+3b=19

3b=1

b=1/3

Therefore, a+b= 6 1/3

I hope this helps!

6 0

3 years ago

Read 2 more answers

A laboratory scale is known to have a standard deviation (sigma) or 0.001 g in repeated weighings. Scale readings in repeated we

weqwewe [10]

Answer:

99% confidence interval for the given specimen is [3.4125 , 3.4155].

Step-by-step explanation:

We are given that a laboratory scale is known to have a standard deviation (sigma) or 0.001 g in repeated weighing. Scale readings in repeated weighing are Normally distributed with mean equal to the true weight of the specimen.

Three weighing of a specimen on this scale give 3.412, 3.416, and 3.414 g.

Firstly, the pivotal quantity for 99% confidence interval for the true mean specimen is given by;

P.Q. = $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample mean weighing of specimen = $\frac{3.412+3.416+3.414}{3}$ = 3.414 g

$\sigma$ = population standard deviation = 0.001 g

n = sample of specimen = 3

$\mu$ = population mean

<em>Here for constructing 99% confidence interval we have used z statistics because we know about population standard deviation (sigma).</em>

So, 99% confidence interval for the population mean, $\mu$ is ;

P(-2.5758 < N(0,1) < 2.5758) = 0.99 {As the critical value of z at 0.5% level

of significance are -2.5758 & 2.5758}

P(-2.5758 < $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ < 2.5758) = 0.99

P( $-2.5758 \times {\frac{\sigma}{\sqrt{n} } }$ < ${\bar X - \mu}$ < $2.5758 \times {\frac{\sigma}{\sqrt{n} } }$ ) = 0.99

P( $\bar X-2.5758 \times {\frac{\sigma}{\sqrt{n} } }$ < $\mu$ < $\bar X+2.5758 \times {\frac{\sigma}{\sqrt{n} } }$ ) = 0.99

<u>99% confidence interval for</u> $\mu$ = [ $\bar X-2.5758 \times {\frac{\sigma}{\sqrt{n} } }$ , $\bar X+2.5758 \times {\frac{\sigma}{\sqrt{n} } }$ ]

= [ $3.414-2.5758 \times {\frac{0.001}{\sqrt{3} } }$ , $3.414+2.5758 \times {\frac{0.001}{\sqrt{3} } }$ ]

= [3.4125 , 3.4155]

Therefore, 99% confidence interval for this specimen is [3.4125 , 3.4155].

6 0

3 years ago