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3 years ago

PLZ HELP!!! I will give you brainliest

Mathematics

1 answer:

Artist 52 [7]3 years ago

6 0

Answer:

141

Step-by-step explanation:

CD = | 4-(-2)| = 6

DB = |3-(-7)| = 10

area of a right triangle

A = (leg 1 x leg2)/2 = (6 x 10)/2 = 30

EB = |3-(-3)| = 6

EF = |-8-(-2)| = 6

area of a square = side^2

A = 6^2 = 36

segment G(and a point with same x coordinate of H)

|8-3| = 5

segment H(and the same point)

|-10-(-8)| = 2

A = (5x2)/2 = 5

segment I(and the same point)

|-8-6| = 14

Area of a rectangle

A = base x width

A = (5 x 14) = 70

total area = 70 + 5 + 36 + 30 = 141

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You only have to answer the last question, number 12 and I will mark brainliest.

Nataly [62]

The answer should be n/5. Hope this helps.

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3 years ago

2^m×2^n=2^-6 and determine which values of m and n are solutions are solutions

Gnoma [55]

Remember
$(x^m)(x^n)=x^{m+n}$
and
if $x^m=x^n$ where x=x then m=n
so
$(2^m)(2^n)=2^{m+n}=2^{-6}$
so
m+n=-6
so test the options

first one works
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answer is first option, m=3 and n=-9

8 0

3 years ago

Read 2 more answers

What is the value of h?

baherus [9]

The value of x can be found by adding the two angles and setting them equal to 180 because they are on a straight line.

3h + 18 + 15h = 180
18h + 18 = 180
18h = 162
h = 9

So the value of h is 9

8 0

3 years ago

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The perimeter of a rectangular garden is 54 feet. The area of the garden is 180 square feet. Find the length and width of the ga

Gala2k [10]

Answer:

15x12

Step-by-step explanation:

3 0

3 years ago

Find the volume V of the solid obtained by rotating the region bounded by the given curves about the specified line. Y = (4/9) x

frez [133]

Answer:

V = 8.06 cubed units

Step-by-step explanation:

You have the following curves:

$y_1=\frac{4}{9}x^2=f(x)\\\\y_2=\frac{13}{9}-x^2=g(x)$

In order to calculate the solid of revolution bounded by the previous curves and the x axis, you use the following formula:

$V=\pi \int_a^b [(g(x))^2-(f(x))^2]dx$ (1)

To determine the limits of the integral you equal both curves f=g and solve for x:

$f(x)=g(x)\\\\\frac{4}{9}x^2=\frac{13}{9}-x^2\\\\\frac{4}{9}x^2+x^2=\frac{13}{9}\\\\\frac{13}{9}x^2=\frac{13}{9}\\\\x=\pm 1$

Then, the limits are a = -1 and b = 1

You replace f(x), g(x), a and b in the equation (1):

$V=\pi \int_{-1}^{1}[(\frac{13}{9}-x^2)^2-(\frac{4}{9}x^2)^2]dx\\\\V=\pi \int_{-1}^1[\frac{169}{81}-\frac{26}{9}x^2+x^4-\frac{16}{81}x^4]dx\\\\V=\pi \int_{-1}^1 [\frac{169}{81}-\frac{26}{9}x^2+\frac{65}{81}x^4]dx\\\\V=\pi [\frac{169}{81}x-\frac{26}{27}x^3+\frac{65}{405}x^5]_{-1}^1\\\\V\approx8.06\ cubed\ units$

The volume of the solid of revolution is approximately 8.06 cubed units

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4 years ago