Answer:
she brought 21 shirts and 2 pants
Step-by-step explanation:
shirts
21× 14.50 = 304.5
357- 304.5 = 52.5
pants
52.5 ÷ 25 = 2.1
Answer:
The highest common factor is 7(3x+1)
Step-by-step explanation:
Here, we want to find the highest common factor of both expressions
As we can see, the highest common factor of 7 and 14 is 7
Now, we have the second expression which is (3x+1)
No matter what the first expression is raised to, it still stands that the highest common factor we shall have there is 3x+ 1 as concerns the term
inside the bracket
Thus, the highest common factor of both terms is 7(3x + 2)
Answer:
rectangle = 2(50) +2(70) + 2(35) = 310
square = 2(32) + 2(12) + 2(24) = 136
Add
136 + 310 = 446 cm^2
SA = 446 cm^2
hope you can give me brainliest !
Step-by-step explanation:
Answer:
Z= (X1`-X2`)- (u1-u2)/
(here s1=σ1 and s2= σ2)
Step-by-step explanation:
Let X1` be the mean of the first random sample of size n1 from a normal population with a mean u1 and known standard deviation σ1.Let X2` be the mean of the second random sample of size n2 from another normal population with a mean u2 and known standard deviation σ2. Then the sampling distribution of the difference X1`-X2` is normally distributed with a mean of u1-u2 and a standard deviation of
. (here s1=σ1 and s2= σ2) In other words the variable
Z= (X1`-X2`)- (u1-u2)/
(here s1=σ1 and s2= σ2)
is exactly standard normal no matter how small sample sizes are . Hence it is used as a test statistic for testing hypotheses about the difference between two population means.
The procedure is stated below.
1) Formulate the null and alternative hypotheses.
2) Decide on significance level ∝
3) Use the test statistic Z= (X1`-X2`)- (u1-u2)/
(here s1=σ1 and s2= σ2)
4) Find the rejection region
5)Compute the value of Z from the sample data
6) Rehect H0 if Z falls in the critical region, accept H0 , otherwise.
Answer:
connect the two hemispheres, ensures that all of this information is kept coordinated. ... You have learned how to add and subtract with signed numbers using models and ... and negative integers to solve problems with positive and negative
Step-by-step explanation: