Answer:
Step-by-step explanation:
AC = length of flagpole = 12 ft
AB = length of shadow = 14 ft
BC = length from the top of the flagpole to the end of the shadow = x ft
Use Pythagorean theorem to find the length of x,
x² = AC² + BC²
= 12² + 14²
= 144 + 196
= 340
x = √340
x = 18.4 ft
The sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec
<h3>Calculating wavelength </h3>
From the question, we are to determine how many times longer is the first sound wave compared to the second sound water
Using the formula,
v = fλ
∴ λ = v/f
Where v is the velocity
f is the frequency
and λ is the wavelength
For the first wave
f = 20 waves/sec
Then,
λ₁ = v/20
For the second wave
f = 16,000 waves/sec
λ₂ = v/16000
Then,
The factor by which the first sound wave is longer than the second sound wave is
λ₁/ λ₂ = (v/20) ÷( v/16000)
= (v/20) × 16000/v)
= 16000/20
= 800
Hence, the sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec
Learn more on Calculating wavelength here: brainly.com/question/16396485
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What do you mean... $245???
y = 80x - 60
Answer is B. y = 80x - 60
Double check:
When x = 1, y = 80(1) - 20 = 80 -60 = 20
When x = 2, y = 80(2) - 20 = 160 -60 = 100
When x = 3, y = 80(3) - 20 = 240 -60 = 180
When x = 4, y = 80(4) - 20 = 320 -60 = 260
When x = 5, y = 80(5) - 20 = 400 -60 = 340
Answer:
x is equal to 7
Step-by-step explanation:
Because the two horizontal lines are parallel, we know that the angles at which they intersect the diagonal line will be identical.
We also know that on either side of the diagonal line, the sum of the angles between that and either of the horizontal lines will be 180.
In short, we know that the two values given have a sum of 180. With that we can quickly solve for x:
(x + 67) + (x + 127) = 180
2x + 194 = 180
2x = -14
x = 7
