We have,
x+y:x-y=3:2
To prove that, x+ y : x - y = 3:2.
x+y=3
And,
x+y = 2
Adding (1) and (2), we get
x+y+x-y=3+2
⇒2x=5
⇒ x =
Put x = in (1), we get
+y=3
⇒ y=3-=
x+y:x-y=
=3:2
So, x+y:x-y=3:2.
Answer:
{ x | x ≥ 0 }
Step-by-step explanation:
Given,
There is a straight line started from (0, 9) and passes through (8, 1),
∵ In the coordinate plan, the values of x are arranged in increasing order to the right side of the y-axis,
Thus, the line is defined for all real values of x greater than 0,
Hence, Domain of the line = All real numbers greater than equal to 0,
i.e. { x | x ≥ 0 }
Thus, FIRST OPTION is correct.
Answer:
Step-by-step explanation:
I have a app called photomath, I really hope this works.
