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3 years ago

Carlie used a coupon and paid $9.99 for pizza that normally costs $14.99. What is the percent of change?

1 answer:

6 0

Charlie used a coupon and pos 9.99 for a pizza and it normally costs 15.99 14* the percentage of the change would be %1.28

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Jack and Jim sign up with an online music store. Jack chooses 15 downloads for $19.75, and Jim chooses 40 downloads for $43.50.

lina2011 [118]

The answer would be A. The registration fee is $5.50, and the cost per download is $0.95.

Solution
Let x = registration fee
y = cost/downloads

Jack
15y + x = 19.75 ; x = 19.75 - 15y
Jim
40y + x = 43.50

Thus,
40y + x = 43.50
40y + 19.75 - 15y = 43.50
25y = 23.75
y= 0.95

for x,
x = 19.75 - 15y
x = 19.75 - 15( 0.95)
x= 19.75 -14.25
x = 5.5

3 0

3 years ago

Can someone help me part 2

Otrada [13]

Step-by-step explanation:

y = ¼x + 2

m1 = ¼

m of line perpendicular = m2

the formula is : m1×m2 = -1

=> m2 = -1 ÷ m1

= -1 ÷ ¼ = -4

so, the equation is :

y = -4x - 7 (option A)

3 0

3 years ago

Lisa drank 7/16 of a bottle of water during the soccer game. Julianne drank 2/3 of the water in a bottle that was the same size

frez [133]

Answer:

julianne drank by about .1 tenth

Step-by-step explanation:

5 0

3 years ago

Given a 30-60-90 triangle with a long leg of 9 in, determine the length of the hypotenuse.

aniked [119]

Answer:

10.38 in

Step-by-step explanation:

Long side would be opposite to 60°.

Since, side opposite to 60° is root 3 upon 2 times of hypotenuse.

$9 = \frac{ \sqrt{3} }{2} \times hypotenuse \\ \\ hypotenuse = \frac{9 \times 2}{ \sqrt{3} } \\ = \frac{18}{ \sqrt{3} } = \frac{18 \sqrt{3} }{3} = 6 \sqrt{3} = 6 \times 1.73 \\ \: \: \: \red{ \bold{hypotenuse = 10.38 \: in}}$

8 0

3 years ago

Ex 3.6 6. find the area enclosed between the curve y= -2x²-5x+3 and the x-axis

Xelga [282]

When y=0,

$-2{ x }^{ 2 }-5x+3=0\\ \\ 2{ x }^{ 2 }+5x-3=0\\ \\ \left( 2x-1 \right) \left( x+3 \right) =0$

$\\ \\ \therefore \quad x=\frac { 1 }{ 2 } \\ \\ \therefore \quad x=-3$

--------------------

$\int _{ -3 }^{ \frac { 1 }{ 2 } }{ -2{ x }^{ 2 } } -5x+3dx$

$\\ \\ ={ \left[ -\frac { { 2x }^{ 2+1 } }{ 2+1 } -\frac { 5{ x }^{ 1+1 } }{ 1+1 } +3x \right] }_{ -3 }^{ \frac { 1 }{ 2 } }$

$\\ \\ ={ \left[ -\frac { 2{ x }^{ 3 } }{ 3 } -\frac { 5{ x }^{ 2 } }{ 2 } +3x \right] }_{ -3 }^{ \frac { 1 }{ 2 } }$

$\\ \\ \\ =\left\{ -\frac { 2 }{ 3 } { \left( \frac { 1 }{ 2 } \right) }^{ 3 }-\frac { 5 }{ 2 } { \left( \frac { 1 }{ 2 } \right) }^{ 2 }+3\left( \frac { 1 }{ 2 } \right) \right\} -\left\{ -\frac { 2 }{ 3 } { \left( -3 \right) }^{ 3 }-\frac { 5 }{ 2 } { \left( -3 \right) }^{ 2 }+3\left( -3 \right) \right\}$

$\\ \\ \\ =-\frac { 2 }{ 3 } \cdot \frac { 1 }{ 8 } -\frac { 5 }{ 2 } \cdot \frac { 1 }{ 4 } +\frac { 3 }{ 2 } -\left\{ -\frac { 2 }{ 3 } \left( -27 \right) -\frac { 5 }{ 2 } \cdot 9-9 \right\}$

$\\ \\ =-\frac { 2 }{ 24 } -\frac { 5 }{ 8 } +\frac { 3 }{ 2 } -\left\{ \frac { 54 }{ 3 } -\frac { 45 }{ 2 } -9 \right\}$

$\\ \\ =-\frac { 2 }{ 24 } -\frac { 15 }{ 24 } +\frac { 36 }{ 24 } -\frac { 54 }{ 3 } +\frac { 45 }{ 2 } +9$

$\\ \\ =\frac { 19 }{ 24 } -\frac { 54 }{ 3 } +\frac { 45 }{ 2 } +\frac { 18 }{ 2 } \\ \\ =\frac { 19 }{ 24 } -\frac { 54 }{ 3 } +\frac { 63 }{ 2 }$

$\\ \\ =\frac { 343 }{ 24 }$

Answer: 343/24 units squared.

6 0

3 years ago

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