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inn [45]
2 years ago
9

Tia invests $2,500 at an interest rate of 4%, compounded quarterly, and another $2,500 at an interest rate of 3.75%, compounded

annually. How much are the investments worth at the end of 5 years?
A) $5,193.75
B) $5,968.7
C) $6,241.20
​ D) $6,055.73
Mathematics
1 answer:
Radda [10]2 years ago
5 0
I’m pretty sure the answer is A I hope that helps :)
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Find the diagonal of a square whose sides are of the given measure.<br><br> Given =
Contact [7]

Answer:

7\sqrt{42}

Step-by-step explanation:

The diagonal is the hypotenuse of the right triangle with legs 7\sqrt{3}

Use Pythagoras' identity to solve for the diagonal d

The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, that is

d² = (7\sqrt{3})² + (7\sqrt{3})²

    = 147 + 147

    = 294 ( take the square root of both sides )

d = \sqrt{294} = 7\sqrt{42} ≈ 45.37 ( to 2 dec. places )

6 0
2 years ago
Which of the following is true for the relation f(x) = x2 + 8? Only the inverse is a function. Both the equation and its inverse
Alchen [17]

<u>ANSWER</u>

Only the equation is a function

<u>EXPLANATION</u>

f(x)=x^2+8 is graphed above with its inverse f^{-1}(x)=\pm \sqrt{x-8}.


We perform the vertical line test for both the equation and its inverse.


The equation f(x)=x^2+8 passed the vertical line hence it is a function.

However, f^{-1}(x)=\pm \sqrt{x-8} failed the vertical line test, hence it is not a function.


3 0
3 years ago
Which conic section does the equation below describe? x+2^2=4y-3
Dmitry [639]

Answer: Circle

Step-by-step explanation:

6 0
2 years ago
I need help with Which table shows the correct methods used to justify the solution steps?
12345 [234]

Answer:

x = 8

Step-by-step explanation:

3 (x - 5) + 7x = 65

3x - 15 + 7x = 65

10x - 15 = 65

10x = 80

x = 8

5 0
2 years ago
Read 2 more answers
Plz help me well mark brainliest if correct!!...
IRISSAK [1]

Answer:

A/5

Step-by-step explanation:

There are 2 people after 5 in the the 4| part and 3 under 6 in the 5| part.

5 0
2 years ago
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