Given, the charges to clip a dog's nail = $n
The charges to wash the dog = $w
The charges to cut a dog's hair = $h
The total charges Jasmin take for 1 dog = $n+$w+$h = $(n+w+h)
For 4 dogs we can get total charges by multiplying the total charge for 1 dog with 4.
So, the total charges for 4 dogs = $(n+w+h) × 4 = $ 4(n+w+h) = $(4n+4w+4h)
So we have got the required answer.
The total charges for 4 dogs = $ 4(n+w+h) = $(4n+4w+4h)
Answer:
8.9 lb
Step-by-step explanation:
I divided 47.17 by 5.3
47.17÷5.3= 8.9
then to check my answer I multiplied 8.9 by 5.3 and got 47.17
hope this helps <3
Answer:
Grade A: 
Grade B: 
Grade C: 
Grade D: 
Step-by-step explanation:
Problems of normally distributed samples can be solved using the Z score table.
The Z score of a measure represents how many standard deviations it is above or below the mean of all the measures.
Each Z score has a pvalue. This represents the percentile of the measure.
In this problem, we have that:
The upper 16% of the class get A grades. The upper 16% has a pvalue of at least 100% = 16% = 84% = 0.84. This is
.
The middle 34% of the class get B grades. The middle 34% has a pvalue of at least 84%-35% = 50% = 0.5 and at most 0.84. This is
.
Those between a pvalue of 0.5-0.34 = 0.16 and 0.5 get get grade C.
has a pvalue of 0.16. So a grade C is in the interval
.
Those with Z lesser than -1 get grades D and F