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2 years ago

Can SOmeone please help me i need to get a good grade on this please!!!!!!

Mathematics

1 answer:

Rudik [331]2 years ago

3 0

Answer:

20 Units

Step-by-step explanation:

Hight times length/by half is tribular prism Formula

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A Stegosaurus eats six and two fifths big leaves for breakfast and three and one fifth big leaves for lunch. How many leaves did

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Answer:

9 and 3/5

Step-by-step explanation:

Nine and Three Fifths

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3 years ago

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attashe74 [19]

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Step-by-step explanation:

Acc to question, the workers have installed 240 chairs in 4 days which equals 60 chairs in 1 day.

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2 years ago

Multiply and show all steps please!!

Mazyrski [523]

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3 years ago

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Using a linear approximation, estimate f(2.1), given that f(2) = 5 and f'(x) = √3x-1.

algol [13]

Answer:

$f\left( {2.1} \right) \approx 5.22360$ .

Step-by-step explanation:

The linear approximation is given by the equation

${f\left( x \right) \approx L\left( x \right) }={ f\left( a \right) + f^\prime\left( a \right)\left( {x - a} \right).}$

Linear approximation is a good way to approximate values of $f(x)$ as long as you stay close to the point $x= a$ , but the farther you get from $x=a$ , the worse your approximation.

We know that,

$a=2\\f(2) = 5\\f'(x) = \sqrt{3x-1}$

Next, we need to plug in the known values and calculate the value of $f(2.1)$ :

${L\left( x \right) = f\left( 2 \right) + f^\prime\left( 2 \right)\left( {x - 2} \right) }=5+\sqrt{3(2)-1}(x-2) =5+\sqrt{5}(x-2)$

Then

$f\left( {2.1} \right) \approx 5+\sqrt{5}(2.1-2)\approx5.22360$ .

6 0

3 years ago

An organic farm has been growing an heirloom variety of summer squash. A sample of the weights of 40 summer squash revealed that

natta225 [31]

Answer:

b. 0.0228

Step-by-step explanation:

We are given that

n=40

Mean, $\mu=402.7 g$

Standard deviation, $\sigma=8.8$ g

We have to find the probability hat the mean weight for a sample of 40 summer squash exceeds 405.5 grams.

$P(x>405.5)=P(\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}>\frac{405.5-402.7}{\frac{8.8}{\sqrt{40}}})$

$P(x>405.5)=P(Z>\frac{2.8}{\frac{8.8}{\sqrt{40}}})$

$P(x>405.5)=P(Z>2.01)$

$P(x>405.5)=1-P(Z\leq 2.01)$

$P(x>405.5)=1-0.977784$

$P(x>405.5)=0.022216$

Hence, option b is correct.

5 0

2 years ago