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Ray Of Light [21]

3 years ago

14

The coach of a tennis team is holding tryouts and can take only 2 more players for the team. There are 5 players trying out. How

many different groups of 2 players could possibly be chosen?

1 answer:

BlackZzzverrR [31]3 years ago

4 0

Answer:

10 possible combinations of 2 player groups

Step-by-step explanation:

used a combinations calculator

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LenKa [72]

11x11=121
$140-121=19
19/7=
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3 0

3 years ago

For the write a story just make your own problem and answer it idk wut the the other one is

zavuch27 [327]

Answer:

1.) Alex and Jemma decided that they will separate the dozen doughnuts that they bought. Since Jemma loved doughnuts she got 7, and Alex got 5.

2.) 35:49

Divide 35 and 5.

35/5=7

Multiply 7 by 7.

7 x 7=49.

The missing side will be 35:49

4 0

3 years ago

Find the product (2x+5)^3 . Write your answer in standard form

seropon [69]

Formula for this case is

(a+b)∧3=a∧3+3a∧2b+3ab∧2+b∧3

(2x+5)∧3=(2x)∧3+3*(2x)∧2*5+3*2x*5∧2+5∧3=8 x∧3+3*4x∧2*5+3*2x*25+125=

=8x∧3+60x∧2+150x+125

Good luck!!!

5 0

3 years ago

Perform the indicated operation. 10 3/7 + 19 5/9

DanielleElmas [232]

Given expression is

$10 \frac{3}{7} + 19 \frac{5}{9}$

Now convert mixed fraction as improper fraction as

$10 \frac{3}{7} + 19 \frac{5}{9} = \frac{10*7 + 3}{7} + \frac{19*9+5}{9}$
                                                         $= \frac{73}{7} + \frac{176}{9}$
                                                          $= \frac{73*9 + 176 * 7}{63}$
                                                         $= \frac{657 + 1232}{63} = \frac{1889}{63}$
Now we can convert $\frac{1889}{63 } = 29 \frac{62}{63}$

So the answer is $29 \frac{62}63}$

4 0

3 years ago

Read 2 more answers

Helpppppp!!!!!!!! pleaseee!!!!!!!!!!

vovangra [49]

Adding all of the areas together:

5 x 6 = 30

4 x 6 = 24

3 x 6 = 18

4^2 + 3^2 = 16 + 9 = 25(square root) = 5

" " = 5

30 + 24 + 18 + 5 + 5 = 82 ft^2

7 0

3 years ago