Answer:
Step-by-step explanation:
Using six random samples, the average number of catfish in the samples was 5.7
Answer:
1. R = 8 ohms 2. V = 32 volts
Step-by-step explanation:
<h3>1. We have,</h3>
Voltage, V = 16 V
Current, I = 2 A
We need to find the resistance of the circuit. Using Ohm's law,
V = IR
So,

2. Current, I = 8 A
Resistance, R = 4 ohms
We need to find the voltage of the circuit. Using Ohm's law again,
V = 8 × 4
V = 32 volts
Hence, this is the required solution.
Answer:
90 calories
Step-by-step explanation:
Calories : quantity of food
there are 300 calories in 100 g of a certain food
300 calories : 100 g food
how many calories are there in a 30 g portion of food
Let x = number of calories
x calories : 30 g food
Equate both ratios
300 calories : 100 g food = x calories : 30 g food
300/100 = x/30
300 * 30 = 100 * x
9000 = 100x
x = 9000/100
x = 90
x = number of calories = 90 calories
1. {2, 7, 14, 12, 13, 21, 12, 12, 6, 8, 12)<br>
Mean -<br>
Median -<br>
Mode -
Marysya12 [62]
Step-by-step explanation:
mean is when you add all of them up and then divide by how many numbers there are.
median is the number In the middle .the middle number is 21 .
mode : number that appears the most . answer is 12
Answer:
The equations that represent an exponential decay are;
A; [y = (0.1)ˣ]
B; [y = 2·(0.3)ˣ]
Step-by-step explanation:
An exponential decay is given by the following formula;
y = a·bˣ
Where;
b < 1
For option A, we have; [y = (0.1)ˣ]
Here; a = 1, b = 0.1 < 1, therefore, the function represents an exponential decay
For option B, we have; [y = 2·(0.3)ˣ]
Here; a = 2, b = 0.3 < 1, therefore, the function represents an exponential decay
For option C, we have; ![\left[y = \left(\dfrac{4}{3} \right)^x\right]](https://tex.z-dn.net/?f=%5Cleft%5By%20%3D%20%5Cleft%28%5Cdfrac%7B4%7D%7B3%7D%20%5Cright%29%5Ex%5Cright%5D)
Here; a = 1, b =
, therefore, the function does not represent an exponential decay
For option D, we have; ![\left[y = \left(\dfrac{7}{5} \right)^x\right]](https://tex.z-dn.net/?f=%5Cleft%5By%20%3D%20%5Cleft%28%5Cdfrac%7B7%7D%7B5%7D%20%5Cright%29%5Ex%5Cright%5D)
Here; a = 1, b =
, therefore, the function does not represent an exponential decay