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Novay_Z [31]
3 years ago
13

Explain why the net shown here cannot be the net of a cube

Mathematics
1 answer:
Schach [20]3 years ago
5 0

Answer:

there is an extra square missing

Step-by-step explanation:

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What is 44 percent of 1,295<br><br> Wander this if you need points <br><br> It’s 569.8
faust18 [17]
It’s 569.8
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4 0
3 years ago
A golf ball of diameter 1.68 inches rolls a distance of 4m in a straight line. How many times does the ball. completely? (1 inch
marin [14]

Answer: 29.9

Step-by-step explanation:

We know that

1 m = 100 cm

4 m = 400 cm

Circumference of ball

= 3.14 x

= 13.37 cm

400 / 13.37

4 0
2 years ago
Can anyone please help with my last math problem pls all of my assignments gotta be turned in by tonight so I would really appre
Evgen [1.6K]

5 points is not enough

3 0
3 years ago
Read 2 more answers
Can someone confirm this? is it correct?
EastWind [94]
<span>60 Sorry, but the value of 150 you entered is incorrect. So let's find the correct value. The first thing to do is determine how large the Jefferson High School parking lot was originally. You could do that by adding up the area of 3 regions. They would be a 75x300 ft rectangle, a 75x165 ft rectangle, and a 75x75 ft square. But I'm lazy and another way to calculate that area is take the area of the (300+75)x(165+75) ft square (the sum of the old parking lot plus the area covered by the school) and subtract 300x165 (the area of the school). So (300+75)x(165+75) - 300x165 = 375x240 - 300x165 = 90000 - 49500 = 40500 So the old parking lot covers 40500 square feet. Since we want to double the area, the area that we'll get from the expansion will also be 40500 square feet. So let's setup an equation for that: (375+x)(240+x)-90000 = 40500 The values of 375, 240, and 90000 were gotten from the length and width of the old area covered and one of the intermediate results we calculated when we figured out the area of the old parking lot. Let's expand the equation: (375+x)(240+x)-90000 = 40500 x^2 + 375x + 240x + 90000 - 90000 = 40500 x^2 + 615x = 40500 x^2 + 615x - 40500 = 0 Now we have a normal quadratic equation. Let's use the quadratic formula to find its roots. They are: -675 and 60. Obviously they didn't shrink the area by 675 feet in both dimensions, so we can toss that root out. And the value of 60 makes sense. So the old parking lot was expanded by 60 feet in both dimensions.</span>
8 0
3 years ago
Explain how to determine if you have a direct variation or proportional relationship
neonofarm [45]

Answer:

straight line that passes through the origin

Step-by-step explanation:

Two variables are said to have a direct variation or proportional relationship if it can be represented by y = kx, where k is a constant.

Comparing this with the equation of a straight line y = mx + b, where m is the slope of the line and b is the y intercept (value of y when x = 0), We can tell if the say that the graph of a direct variation or proportional relationship is a straight line with no y intercept (b = 0, that is it passes through the origin).

8 0
3 years ago
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