The answer is six equal sized links because two, three, and six, are all factors of six.
Answer:
in a region with a letter
Step-by-step explanation:
For a certainty, then probability is 1.
That means sum of probability of all events in the sample space.
This means P(A)+P(B)+P(C)+P(D)=1
This is equivalent to:
P(A or B or C or D)=1
Hence for certainty, the region must be:
A or B or C or D
So the correct answer is in a region with a letter.
Answer:
Step-by-step explanation:
pls find below
hope this helps
![\bf \qquad \qquad \textit{Future Value of an ordinary annuity} \\\\ A=pymnt\left[ \cfrac{\left( 1+\frac{r}{n} \right)^{nt}-1}{\frac{r}{n}} \right]](https://tex.z-dn.net/?f=%5Cbf%20%5Cqquad%20%5Cqquad%20%5Ctextit%7BFuture%20Value%20of%20an%20ordinary%20annuity%7D%0A%5C%5C%5C%5C%0AA%3Dpymnt%5Cleft%5B%20%5Ccfrac%7B%5Cleft%28%201%2B%5Cfrac%7Br%7D%7Bn%7D%20%5Cright%29%5E%7Bnt%7D-1%7D%7B%5Cfrac%7Br%7D%7Bn%7D%7D%20%5Cright%5D)
![\bf \begin{cases} A= \begin{array}{llll} \textit{original amount}\\ \textit{already compounded} \end{array} & \begin{array}{llll} \end{array}\\ pymnt=\textit{periodic payments}\to & \begin{array}{llll} 485\cdot 12\\ \underline{5280} \end{array}\\ r=rate\to 6\%\to \frac{6}{100}\to &0.06\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{a year, thus once} \end{array}\to &1\\ t=years\to &4 \end{cases} \\\\\\ ](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Bcases%7D%0AA%3D%0A%5Cbegin%7Barray%7D%7Bllll%7D%0A%5Ctextit%7Boriginal%20amount%7D%5C%5C%0A%5Ctextit%7Balready%20compounded%7D%0A%5Cend%7Barray%7D%20%26%0A%5Cbegin%7Barray%7D%7Bllll%7D%0A%0A%5Cend%7Barray%7D%5C%5C%0Apymnt%3D%5Ctextit%7Bperiodic%20payments%7D%5Cto%20%26%0A%5Cbegin%7Barray%7D%7Bllll%7D%0A485%5Ccdot%2012%5C%5C%0A%5Cunderline%7B5280%7D%0A%5Cend%7Barray%7D%5C%5C%0Ar%3Drate%5Cto%206%5C%25%5Cto%20%5Cfrac%7B6%7D%7B100%7D%5Cto%20%260.06%5C%5C%0An%3D%0A%5Cbegin%7Barray%7D%7Bllll%7D%0A%5Ctextit%7Btimes%20it%20compounds%20per%20year%7D%5C%5C%0A%5Ctextit%7Ba%20year%2C%20thus%20once%7D%0A%5Cend%7Barray%7D%5Cto%20%261%5C%5C%0A%0At%3Dyears%5Cto%20%264%0A%5Cend%7Bcases%7D%0A%5C%5C%5C%5C%5C%5C%0A)
![\bf A=5280\left[ \cfrac{\left( 1+\frac{0.06}{1} \right)^{1\cdot 4}-1}{\frac{0.06}{1}} \right]](https://tex.z-dn.net/?f=%5Cbf%20A%3D5280%5Cleft%5B%20%5Ccfrac%7B%5Cleft%28%201%2B%5Cfrac%7B0.06%7D%7B1%7D%20%5Cright%29%5E%7B1%5Ccdot%20%204%7D-1%7D%7B%5Cfrac%7B0.06%7D%7B1%7D%7D%20%5Cright%5D)
Joe is making $485 payments monthly, but the amount gets interest on a yearly basis, not monthly, so the amount that yields interest is 485*12
also, keep in mind, we're assuming is compound interest, as opposed to simple interest