The recursive formula of the geometric sequence is given by option D; an = (1) × (5)^(n - 1) for n ≥ 1
<h3>How to determine recursive formula of a geometric sequence?</h3>
Given: 1, 5, 25, 125, 625, ...
= 5
an = a × r^(n - 1)
= 1 × 5^(n - 1)
an = (1) × (5)^(n - 1) for n ≥ 1
Learn more about recursive formula of geometric sequence:
brainly.com/question/10802330
#SPJ1
Answer:
x = -3
Step-by-step explanation:
Since they give you the function in binomial factor form, it is very straight forward to find what its zeroes are: Those x-values for which any of the binomial factors renders zero would be a so called "zero" of the function.
We examine each of these binomial factors [ (x+3), (x-7) and (x+5) and notice that for the factor:
(x+3) to be zero, x needs to be equal to "-3",
(x-7) to be zero, , x needs to be equal to "7",
(x+5) to be zero, , x needs to be equal to "-5".
therefore, from the options they give you, only "x= -3" is correct.