Step-by-step explanation:
<u>Complete the operation, find the quotient and match with correct option:</u>
- 44.1/4.9 = 9
- 32.8/8.2 = 4
- 43.2/3.6 = 12
- 161.2/5.2 = 31
- 93.6/7.2 = 13
The maximum weight that could be held would be 32 pounds. or six five pound weights taking up 18 inches of space, and weighing 30 Lbs, and two one pound weights adding another two inches. You could achieve a greater weight if you had a weight of one-half inch, in which case you could take six 5 lb weights and 1 two pound weight, then you could add a half inch weight bringing the weight to over 32 inches. Since we don't have a half inch weight we can't raise the weight above 32lbs.
Answer: 1.4
Step-by-step explanation: First, swap the sides of the equation so that the one with the variable can be in front.
So, its 2y=2.8
To solve this, you simply divide both sides of the equation by 2.
2 divided by 2 is 0. That leaves you with the y by itself. Then, 2.8 divided by 2 is 1.4
So, y=1.4
This is a classic example of a 45-45-90 triangle: it's a right triangle (one angle of 90) & two other sides of the same length, which means two angles of the same length (and 45 is the only number that will work). With a 45-45-90 triangle, the lengths of the legs are easy to determine:
45-45-90
1-1-sqrt2
Where the hypotenuse corresponds to sqrt2.
Now, your hypotenuse is 10.
To figure out what each leg is, divide 10/sqrt2 (because sqrt2/sqrt2 = 1, which is a leg length in the explanation above).
Problem: you can't divide by radicals. So, we'll have to rationalize the denominator:
(10•sqrt2)/(sqrt2•sqrt2)
This can be rewritten:
10sqrt2/sqrt(2•2)
=10sqrt2/sqrt4
=10sqrt2/2
=5sqrt2
Hope this helps!!
I will give you the formula and teach you how to solve this. Let’s start with finding the area of both the right triangles.
The formula is, base x height / 2 = area
Triangle 1 - 2x8/2 = 16/2 = 8
Triangle 2 - 2x8/2 = 16/2 = 8
Rectangle - 8x3 = 24
Add them up: 24 + 8 + 8 = 40 square feet
I hope this wasn’t to confusing
