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Genrish500 [490]
3 years ago
12

4. -5x-15=-3x+23

Mathematics
1 answer:
AlladinOne [14]3 years ago
6 0

Answer:

x=-19  x=30

Step-by-step explanation:

-5x-15=-3x+23

    -23      -23

-5x-38=-3x

+5x        +5x

-38=2x

/2       /2

-19=x

-107-7x=73-13x

-73         -73

-180-7x=-13x

      +7x   +7x

-180=-6x

30=x

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What is the other zero of the quadratic function?
svetoff [14.1K]

Answer:

he zeros of a quadratic equation are the points where the graph of the quadratic equation crosses the x-axis.

Step-by-step explanation:

3 0
3 years ago
Simply (1+square root 3) (2-square root 3)<br> On edg
-Dominant- [34]

Answer:

Step-by-step explanation:

(1+√3)(2-√3)=1(2-√3)+√3(2-√3)

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3 years ago
Write the multiplicative inverse of <br>a) -13/19​
irga5000 [103]

Answer:

-  \frac{19}{13}

Step-by-step explanation:

the \: multiplicative \: inverse \: of \:  \\  -  \frac{13}{19}  =  -  \frac{19}{13}

Product of a number and its multiplicative inverse should be equal to 1.

So,

\bigg ( -  \frac{13}{19} \bigg)  \bigg ( -  \frac{19}{13} \bigg)

= \frac{13}{19}\times  \frac{19}{13}

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3 0
3 years ago
Describe the graph of the function.
gayaneshka [121]

Answer:

The answer is option 1.

Step-by-step explanation:

Axis of symmetry means the middle x-coordinates of the parabola. So in order to find the x value, you have to find the TP which is Turning Point by using Completing the Square :

{(x +  \frac{b}{2} )}^{2}  -  {( \frac{b}{2} )}^{2}  + c = 0

Let y = 0,

2{x}^{2}  + 12x - 15 = 0

2( {x}^{2}  + 6x -  \frac{15}{2} ) = 0

{( {x +  \frac{6}{2}) }^{2}  - ( { \frac{6}{2} )}^{2}  -  \frac{15}{2} } = 0

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( {x + 3)}^{2}  - 9 -  \frac{15}{2}  = 0

(x { + 3)}^{2}  -   \frac{33}{2}   = 0

2(x { + 3)}^{2}  - 33 = 0

Next, you have to solve the x value :

x + 3 = 0

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7 0
3 years ago
Topic: Finite Geometric Sums <br> what is the value of ..
Juli2301 [7.4K]
For i=1 ===> Sum=4

for i=2===> Sum=2

for I=3===> Sum=1

Hence the answer is 7

Or you could have use the Sum formula of a GP:

Sum = a(1-r)^n/(1-r), with a=1, r=1/2 & n=3
6 0
3 years ago
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