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RideAnS [48]
2 years ago
10

HELP ME PLEASE HELP HELP HELP WALLAHI HELP

Mathematics
1 answer:
enyata [817]2 years ago
8 0

9514 1404 393

Answer:

  48

Step-by-step explanation:

The Pythagorean theorem tells you the square of the hypotenuse (longest side) is the sum of the squares of the other two sides. Let x represent the unknown side.

  73² = x² +55²

  5329 = x² +3025 . . . evaluate the squares

  2304 = x² . . . . . . . . . subtract 3025 from both sides

  48 = x . . . . . . . . . . . . take the square root of both sides

The exact length of the third side is 48.

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Brilliant_brown [7]

The number of ways in which the position of one person in charge of research and one person in charge of marketing can be chosen from the board of 16 members is <u>240 ways</u>. Computed using permutations.

The permutation is the way of choosing a set of objects from a larger set of objects in a specific sequence.

If we are choosing r number of objects, from n number of objects in a specific sequence, then we follow permutation, and it is given as:

nPr = n!{(n - r)!}.

In the question, we are asked to find the number of ways in which the position of one person in charge of research and one person in charge of marketing can be chosen from the board of 16 members.

Since the position is to be chosen in a specific order, we will follow permutation.

The number of positions to be chosen (r) = 2.

The number of members (n) = 16.

Thus, the number of ways is given as:

nPr = n!{(n - r)!},

or, 16P2 = 16!{(16 - 2)!},

or, 16P2 = 16!/14! = 15*16 = 240.

Thus, the number of ways in which the position of one person in charge of research and one person in charge of marketing can be chosen from the board of 16 members is <u>240 ways</u>. Computed using permutations.

Learn more about permutations at

brainly.com/question/4658834

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6 0
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Help me asap please!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
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