explain why the function f(x)= 5x-15/x-3 is not asymptotic to the line x=3. sketch the graph of this function.
1 answer:
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Hi there!
Let's solve this equation step by step!
6f + 9g = 3g + f
To solve for f, we need to bring all the terms in the equation with an f in it to the left, and all the other terms (with a g) to the right.
First subtract f from both sides.
5f + 9g = 3g
Now subtract 9g from both sides.
5f = -6g
And finally divide both sides by 5.
f = (-6/5)g
Hence, your answer;
~ Hope this helps you!
Let's solve this equation step by step!
6f + 9g = 3g + f
To solve for f, we need to bring all the terms in the equation with an f in it to the left, and all the other terms (with a g) to the right.
First subtract f from both sides.
5f + 9g = 3g
Now subtract 9g from both sides.
5f = -6g
And finally divide both sides by 5.
f = (-6/5)g
Hence, your answer;
~ Hope this helps you!
Answer: 69,904
Explanation:
g(-16)= (-16)^4-(-16)^3+(-16)^2-(-16)
g(-16)= (65,536)-(-4,096)+(256)-(-16)
g(-16)= 65,536+4,096+256+16
g(-16)=69,904
Explanation:
g(-16)= (-16)^4-(-16)^3+(-16)^2-(-16)
g(-16)= (65,536)-(-4,096)+(256)-(-16)
g(-16)= 65,536+4,096+256+16
g(-16)=69,904
After 24 hours, 35.4% of the initial dosage remains on the body.
<h3>What percentage of the last dosage remains?</h3>
The exponential decay is written as:
Where A is the initial value, in this case 2.8mg.
k is the constant of decay, given by the logarithm of 2 over the half life, in this case, is:
Replacing all that in the above formula, and evaluating in x = 24 hours we get:
The percentage of the initial dosage that remains is:
If you want to learn more about exponential decays:
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