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3 years ago

12

Yo is someone finna do my aleks?… I only need 8topics but if u can do at least 4 that’s good enough (plz only awnser if ur willi

ng to do it)
:)
Username- Dwright4387
Password- wcsmath96

2 answers:

MrMuchimi3 years ago

8 0

Answer:

dont put your info up:)

Step-by-step explanation:

Lelechka [254]3 years ago

6 0

Answer:

4

Step-by-step explanation:

You might be interested in

Olenka [21]

Answer:

d = -1/3, 0

Step-by-step explanation:

Subtract the constant on the left, take the square root, and solve from there.

(6d +1)^2 + 12 = 13 . . . . given

(6d +1)^2 = 1 . . . . . . . . . .subtract 12

6d +1 = ±√1 . . . . . . . . . . take the square root

6d = -1 ±1 . . . . . . . . . . . .subtract 1

d = (-1 ±1)/6 . . . . . . . . . . divide by 6

d = -1/3, 0

_____

Using a graphing calculator, it is often convenient to write the function so the solutions are at x-intercepts. Here, we can do that by subtracting 13 from both sides:

f(x) = (6x+1)^ +12 -13

We want to solve this for f(x)=0. The solutions are -1/3 and 0, as above.

4 0

3 years ago

Is an arithmetic sequence a function?

Sphinxa [80]

Yes it is a linear function

3 0

2 years ago

The radius of a circle is 15 inches. A chord is drawn 4 inches from the center of the circle. How long is the chord?

Alex73 [517]

Let X represent the length of the chord.

By using Pythagoras' Theorem:

4^2 + (X/2)^2 = 15^2

(X^2)/4 = 209

X^2 = 836

X = 28.91

6 0

3 years ago

Ann is adding water to a swimming pool at a constant rate. The table below shows the amount of water in the pool after different

N76 [4]

Answer:

(a) As time increases, the amount of water in the pool increases.

11 gallons per minute

(b) 65 gallons

Step-by-step explanation:

From inspection of the table, we can see that <u>as time increases, the amount of water in the pool increases</u>.

We are told that Ann adds water at a constant rate. Therefore, this can be modeled as a linear function.

The rate at which the water is increasing is the <em>rate of change</em> (which is also the <em>slope </em>of a linear function).

Choose 2 ordered pairs from the table:

$\textsf{let}\:(x_1,y_1)=(8, 153)$

$\textsf{let}\:(x_2,y_2)=(12,197)$

Input these into the slope formula:

$\textsf{slope}\:(m)=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{197-153}{12-8}=\dfrac{44}{4}=11$

Therefore, the rate at which the water in the pool is increasing is:

<u>11 gallons per minute</u>

To find the amount of water that was already in the pool when Ann started adding water, we need to create a linear equation using the found slope and one of the ordered pairs with the point-slope formula:

$y-y_1=m(x-x_1)$

$\implies y-153=11(x-8)$

$\implies y-153=11x-88$

$\implies y=11x-88+153$

$\implies y=11x+65$

When Ann had added no water, x = 0. Therefore,

$y=11(0)+65$

$y=65$

So there was <u>65 gallons</u> of water in the pool before Ann starting adding water.

3 0

2 years ago

Read 2 more answers

Ray has found that his new car gets 31 miles per gallon on the highwayand 26 miles per gallon in the city. He recently drove 285

Mkey [24]

Answer:

$Highway = 155\ miles$

$City = 130\ miles$

Step-by-step explanation:

Given

$Highway = 31mi/gallon$

$City = 26mi/gallon$

$Total\ Miles = 285$

$Total\ Gallons = 10$

Required

Determine the number of miles driven on the highway and on the city

Represent the gallons used on highway with h and on city with c.

So, we have:

$c + h = 10$ ---- gallons used

and

$31h + 26c = 285$ --- distance travelled

In the first equation, make c the subject

$c = 10 - h$

Substitute 10 - h for c in the second equation

$31h + 26c = 285$

$31h + 26(10 - h) = 285$

Open bracket

$31h + 260 - 26h = 285$

Collect like terms

$31h - 26h = 285 - 260$

$5h = 25$

Make h the subject

$h = \frac{25}{5}$

$h = 5$

Substitute 5 for h in $c = 10 - h$

$c = 10 - 5$

$c = 5$

If on the highway, he travels 31 miles per gallon, then his distance on the highway is:

$Highway = 31 * 5$

$Highway = 155\ miles$

If in the highway, he travels 26 miles per gallon, then his distance on the highway is:

$City = 26 * 5$

$City = 130\ miles$

8 0

2 years ago