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Elanso [62]
3 years ago
6

The __________ is the serous membrane that covers most digestive organs.

Business
2 answers:
Dvinal [7]3 years ago
6 0

Answer:

Peritoneum

Explanation:

The peritoneum is the serous membrane that covers most digestive organs found in the human body, such as the stomach, large intestine and small intestine

The Peritoneum is made up of two parts:  the external part/outer layer and the internal part/internal layer. the external part known as the parietal peritoneum is strongly attached to the abdominal wall while the internal part known as Visceral Peritoneum is the part that is wrapped around the internal organs of the digestive system located in the  intraperitoneal cavity.

myrzilka [38]3 years ago
3 0

Answer:peritoneum

Explanation:The peritoneum, the serous membrane that forms the lining of the abdominal cavity, covers most of the intra-abdominal organs.

There are two layers of the peritoneum: the outer layer, called the parietal peritoneum, is attached to the abdominal wall; the inner layer, the visceral peritoneum, is wrapped around the internal organs that are located inside the intraperitoneal cavity.

The mesentery is the double layer of visceral peritoneum.

The peritoneum supports the abdominal organs and serves as a conduit for their blood and lymph vessels and nerves.

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Answer:

1) We need a random sample. For this case we assume that the sample selected was obtained using the simple random sampling method.

2) We need to satisfy the following inequalities:

n\hat p =25*0.52= 13 \geq 10

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a. Yes.

Explanation:

For this case we assume that the question is: If in the experiment described we can use the normal approximation for the proportion of interest.

For this case we have a sample of n =25

And we are interested in the proportion of registered students that spend more than 20 minutes to get to school.

X = 13 represent the number of students in the sample selected that have a time more than 20 min.

And then the estimated proportion of interest would be:

\hat p = \frac{X}{n}= \frac{13}{25}= 0.52

And we want to check if we can use the normal approximation given by:

p \sim N (\hat p, \sqrt{\frac{\hat p (1-\hat p)}{n}})

So in order to do this approximation we need to satisfy some conditions listed below:

1) We need a random sample. For this case we assume that the sample selected was obtained using the simple random sampling method.

2) We need to satisfy the following inequalities:

n\hat p =25*0.52= 13 \geq 10

n(1-\hat p) = 25*(1-0.52) =12 \geq 10

So then we satisfy this condition:

3) 10% condition. For this case we assume that the random sample selected n represent less than 10% of the population size N . And for this case we can assume this condition.

So then since all the conditions are satisfied we can conclude that we can apply the normal approximation given by:

p \sim N (\hat p, \sqrt{\frac{\hat p (1-\hat p)}{n}})

So then the answer for this case would be:

a. Yes.

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