All categories

2 years ago

Find the product. 2 4/10 =

Mathematics

1 answer:

AleksAgata [21]2 years ago

3 0

Answer: 2 2/5 is answer decimal answer is 2.4

Step-by-step explanation:

hope this helpss!!

You might be interested in

Let T: Rn → Rn be an invertible linear transformation, and let S and U be functions from Rn into Rn such that

ipn [44]

Answer:

Follows are the solution to this question:

Step-by-step explanation:

$T: 1 \ R^n \to 1 \ R^n$ is invertible lines transformation

$S[T(x)]=x \ and \ V[T(x)]=x \\\\t'x \ \varepsilon\ 1 R^n\\\\$

T is invertiable linear transformation means that is

$T(x) =A x \\\\ where \\\\ A= n \times n \ \ matrix$

and $\ det(A) \neq 0 \ \ that \ is \ \ A^{-1} \ \ exists$

Let

$V \varepsilon\ a\ R^{n} \ consider \ \ u= A^{-1} v \varepsilon 1 R^n\\\\T(u)= A(A^{-1} v)=(A \ A^{-1}) \\\\ v= I_{n \times n} \cdot v = v$

so,

$s[T(u)]=v[T(u)]\\\\s(v)=v(v) \ \ \forall \ \ v \ \ \varepsilon \ \ 1 R^n$

7 0

2 years ago

Alex and bob are playing 5 chess games. Alex is 3 times more likely to win than bob. What is the probability that both of them w

givi [52]

Answer:

12.2%

Step-by-step explanation:

Lets firstly find out the probabilities for Alex and Bob. We know that the prb that Alex wins is 3 times the prob for Bob, so:

P(A) = 3P(B)

And, as these values are probabilities they must sum 1:

P(A) + P(B) = 1

Replacing the first equation in the second:

3P(B) + P(B) = 1

4P(B) = 1

Dividing both sided by 4:

4P(B)/4 = 1/4

P(B) =1/4

So, the probability for Bob is 1/4. Then the probability for Alex is 3*1/4 = 3/4

Now we have to find the probability that both win at least two games. Lets think about the possible combination of cases. As they play 5 games and both have to win at least to there is a remaining game that cane variate, this is, can be won by Alex or Bob. So, we can have:

AABBB

AABBA

Where A is "Alex win" and B is "Bob win" (here we do not pay attention to the order).

Thus, we have to find the probability that Alex wins 3 games and Bob 2 games, and the probability that Alex wins 2 games and Bob 3 games. As the games are independent, i.e., the result of one games does not affect the followings we can just multiply the probabilities:

P(3A and 2B) = (3/4)*(3/4)*(3/4)*(1/4)*(1/4) = 0.42*0.06 = 0.026

P(2A and 3B) = (3/4)*(3/4)*(1/4)*(1/4)*(1/4) = 0.56*0.016 = 0.096

So,

P (at least 2) = P(3A and 2B) + P(2A and 3B) = 0.026 + 0.096 = 0.122 = 12.2%

7 0

3 years ago

What is vaule of f^-1 (-4)

Butoxors [25]

Answer:

-4/f

Step-by-step explanation:

i hope this helps