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3 years ago

15

The jamison family kept a log of the distance they traveled during a trip, as represent by the graph below. During which interva

l was their average speed the greatest

1 answer:

KATRIN_1 [288]3 years ago

4 0

Answer:

20 meter jndbrje fjfjbrne

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Math: what is 2+7-9+11=

vlada-n [284]

2 + 7 - 9 + 11
= 9 - 9 + 11
= 0+ 11
= 11

hope it's helpful !
have a nice day :)

3 0

3 years ago

Read 2 more answers

Two functions f and g represent the profit of two companies, in millions of dollars, about 13 years after they went into busines

hram777 [196]

Answer:

13.253 is correct

Step-by-step explanation:

This table shows 0.1203 and 0.1212 having the most correlation since they are the closest to each other which means 13.253 hours is the closest.

4 0

3 years ago

Can someone please help me and ill mark you as brainlest

Vitek1552 [10]

9514 1404 393

Answer:

F. 30·tan(52°)

Step-by-step explanation:

The mnemonic SOH CAH TOA reminds you of the relationship between the opposite and adjacent sides in a right triangle.

Tan = Opposite/Adjacent

tan(52°) = BD/DL

BD = DL·tan(52°)

The boat-to-dock distance is ...

30·tan(52°) . . . . matches F

6 0

3 years ago

Someone claims that the breaking strength of their climbing rope is 2,000 psi, with a standard deviation of 10 psi. We think the

denpristay [2]

Answer:

The sample size must be greater than 37 if we want to reject the null hypothesis.

Step-by-step explanation:

We are given that someone claims that the breaking strength of their climbing rope is 2,000 psi, with a standard deviation of 10 psi.

Also, we are given a level of significance of 5%.

Let $\mu$ = <u><em>mean breaking strength of their climbing rope</em></u>

SO, Null Hypothesis, $H_0$ : $\mu$ = 2,000 psi {means that the mean breaking strength of their climbing rope is 2,000 psi}

Alternate Hypothesis, $H_A$ : $\mu$ < 2,000 psi {means that the mean breaking strength of their climbing rope is lower than 2,000 psi}

Now, the test statistics that we will use here is One-sample z-test statistics as we know about population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = ample mean strength = 1,997.2956 psi

$\sigma$ = population standard devaition = 10 psi

n = sample size

Now, at the 5% level of significance, the z table gives a critical value of -1.645 for the left-tailed test.

So, to reject our null hypothesis our test statistics must be less than -1.645 as only then we have sufficient evidence to reject our null hypothesis.

SO, T.S. < -1.645 {then reject null hypothesis}

$\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } < -1.645$

$\frac{1,997.2956-2,000}{\frac{10}{\sqrt{n} } } < -1.645$

$(\frac{1,997.2956-2,000}{10}) \times {\sqrt{n} } } < -1.645$

$-0.27044 \times \sqrt{n}< -1.645$

$\sqrt{n}> \frac{-1.645}{-0.27044}$

$\sqrt{n}>6.083$

n > 36.99 ≈ 37.

SO, the sample size must be greater than 37 if we want to reject the null hypothesis.

7 0

3 years ago

I WILL GIVE A CROWN

weeeeeb [17]

kilograms of yellow potatoes bought is 8330 kg

<em><u>Solution:</u></em>

Given that James buys 245 kilograms of red potatoes

He buys yellow potatoes that weigh 34 as much as the red potatoes

To find: kilograms of yellow potatoes bought by James

Let "y" be the kilograms of yellow potatoes bought

Let "r" be the kilograms of red potatoes bought

kilograms of red potatoes bought = 245 kilograms

r = 245 kilograms

From given information,

Yellow potatoes weigh 34 as much as the red potatoes

here "as much as" means product or multiplication

Kilograms of yellow potatoes bought = 34 x kilograms of red potatoes bought

$y = 34 \times 245\\\\y = 8330$

Thus kilograms of yellow potatoes bought is 8330 kg

The answer cannot be expressed in mixed number since whole numbers has no fractional part

7 0

3 years ago