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2 years ago

I need yall help with this one and i can make yall brilientist if u get it right plus yall get 50 points

Chemistry

2 answers:

mixas84 [53]2 years ago

6 0

Answer:

Explanation:

amid [387]2 years ago

4 0

Answer:

C. and B. im pretty sure hope it helps

Explanation:

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9. What lab equipment is used to spread heat when heating to prevent glassware from cracking

Lubov Fominskaja [6]

It's called ”wire gauze”, a metal mesh used with a ring clamp to support glassware over a Bunsen burner. Spreads flame out for more even heating rates.

5 0

3 years ago

3C2H402 atoms in formula

Vanyuwa [196]

3( 2 carbons + 4 hydrogen's + 2 oxygens)

3*(8) = 24

4 0

3 years ago

Calculate the grams of so2 gas present at stp in a 5.9 l container.

nata0808 [166]

<u>Answer:</u> The mass of sulfur dioxide gas at STP for given amount is 16.8 g

<u>Explanation:</u>

At STP conditions:

22.4 L of volume is occupied by 1 mole of a gas.

So, 5.9 L of volume will be occupied by = $\frac{1mol}{22.4L}\times 5.9L=0.263mol$

Now, to calculate the mass of a substance, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Moles of sulfur dioxide gas = 0.263 mol

Molar mass of sulfur dioxide gas = 64 g/mol

Putting values in above equation, we get:

$0.263mol=\frac{\text{Mass of sulfur dioxide gas}}{64g/mol}\\\\\text{Mass of sulfur dioxide gas}=(0.263mol\times 64g/mol)=16.8g$

Hence, the mass of sulfur dioxide gas at STP for given amount is 16.8 g

7 0

3 years ago

Use the definition of molarity to calculate the concentration of 12.34 g of CaSO4 completely dissolved in water, with a solution

Ede4ka [16]

Answer:

[CaSO₄] = 36.26×10⁻² mol/L

Explanation:

Molarity (M) → mol/L → moles of solute in 1L of solution

Let's convert the volume from mL to L

250 mL . 1L/1000 mL = 0.250L

We need to determine the moles of solute. (mass / molar mass)

12.34 g / 136.13 g/mol = 0.0906 mol

M → 0.0906 mol / 0.250L = 36.26×10⁻² mol/L

8 0

3 years ago

What is water's density at 93 ∘C? Assume a constant coefficient of volume expansion. Express your answer with the appropriate un

Ganezh [65]

Answer:

982.5 kg/m³

Explanation:

When the temperature of a fluid increases, it dilates, and because of the variation of the volume, it's density will vary too. The density can be calculated by the expression:

ρ₁ = ρ₀/(1 + β*(t₁ - t₀))

Where ρ₁ is the final density, ρ₀ the initial density, β is the constant coefficient of volume expansion, t₁ the final temperature, and t₀ the initial temperature.

At t₀ = 4°C, the water desity is ρ₀ = 1,000 kg/m³. The value of the constant for water is β = 0.0002 m³/m³ °C, so, for t₁ = 93°C

ρ₁ = 1,000/(1 + 0.0002*(93 - 4))

ρ₁ = 1,000/(1+ 0.0178)

ρ₁ = 982.5 kg/m³

3 0

3 years ago