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mash [69]
3 years ago
8

Identify the solute and solvent in each of the solutions. A. salt ( NaCl ) (NaCl) in water salt: water: B. air (a solution of 78

% N 2 , 78% N2, 21 % O 2 , 21% O2, and various other gases) N 2 : N2: O 2 : O2: C. a solution of 28 % 28% ethanol and 72 % 72% water ethanol: water: D. bronze (an alloy of 95 % 95% copper and 5 % 5% tin) copper:
Chemistry
1 answer:
stira [4]3 years ago
5 0

Answer:

A) solute - NaCl, solvent - water

B) solute - O2 and other gases, solvent - N2

C) solute - ethanol, solvent - water

D) solute - tin, solvent - copper

Explanation:

Solute(s) is/are the minor component(s) in a solution, dissolved in the solvent.

Solvent is the component of a solution that is present in the greatest amount. It is the substance in which the solute is dissolved.

If both solute and solvent exist in equal quantities (such as in a 50% ethanol, 50% water solution), the concepts of "solute" and "solvent" become less relevant, but the substance that is more often used as a solvent is normally designated as the solvent (in this example, water).

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Answer:

1. A. The plant leans toward window.

Explanation:

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3 years ago
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2 years ago
Starting with 2.50 mol of N2 gas (assumed to be ideal) in a cylinder at 1.00 atm and 20.0C, a chemist first heats the gas at con
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Answer:

a)  T_b=590.775k

b)  W_t=1.08*10^4J

d)  Q=3.778*10^4J

d)  \triangle V=4.058*10^4J

Explanation:

From the question we are told that:

Moles of N2 n=2.50

Atmospheric pressure P=100atm

Temperature t=20 \textdegree C

                      t = 20+273

                     t = 293k

Initial heat Q=1.36 * 10^4 J

a)

Generally the equation for change in temperature is mathematically given by

\triangle T=\frac{Q}{N*C_v}

  Where

  C_v=Heat\ Capacity \approx 20.76 J/mol/K

T_b-T_a=\frac{1.36 * 10^4 J}{2.5*20.76 }

T_b-293k=297.775

T_b=590.775k

b)

Generally the equation for ideal gas is mathematically given by

 PV=nRT

For v double

 T_c=2*590.775k

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PV=Wbc

Wbc=(2.20)(8.314)(1181_590.778)

Wbc=10805.7J

Total Work-done W_t

W_t=Wab+Wbc

W_t=0+1.08*10^4

W_t=1.08*10^4J

c)

Generally the equation for amount of heat added is mathematically given by

Q=nC_p\triangle T

Q=2.20*2907*(1181.55-590.775)\\

Q=3.778*10^4J

d)

Generally the equation for change in internal energy of the gas is mathematically given by

\triangle V=nC_v \triangle T

\triangle V=2.20*20.76*(1181.55-293)k

\triangle V=4.058*10^4J

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