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RUDIKE [14]
3 years ago
8

How wide is the central diffraction peak on a screen 2.10 m behind a 0.0328-mm-wide slit illuminated by 568-nm light?

Physics
1 answer:
slava [35]3 years ago
3 0

Answer:

0.0364 m

Explanation:

D = Screen distance = 2.10 m

d = Slit width = 0.0328 mm = 0.0328 x 10⁻³ m

\lambda = Wavelength of light = 568 x 10⁻⁹ m

w = width of the central diffraction peak

Width of the central diffraction peak is given as

w = \frac{D \lambda}{d} \\w = \frac{(2.10) (568\times10^{-9})}{0.0328\times10^{-3}}\\w = 0.0364 m

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Answer:

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Explanation:

From the question,

Net Work done = Net force× distance moved by net force.

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Answer:

a)

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quantities which need magnitude along with direction r called vector quantities such as velocity.

c)

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3 years ago
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