Answer:
1476 J
Explanation:
From the question,
Net Work done = Net force× distance moved by net force.
W' = (F-F')×d................... Equation 1
Where W' = Net work done, F = force applied, F' = Frictional force, d = distance moved.
Given: F = 150 N, F' = 37 N, d = 12 m
Substitute these values into equation 1
W' = (150-37)×12
W' = 123×12
W' = 1476 J.
hence the Net Work done by the object is 1476 J
Answer:
a)
there r two types of motion, uniform and non-uniform
uniform means equal distance travelled at equal intervals of time
and non-uniform is exactly the opposite.
b)
quantities which can be represented by magnitude along r called scalar quantities such as speed.
quantities which need magnitude along with direction r called vector quantities such as velocity.
c)
velocity=10m/s
acceleration = u-v/s i.e initial final velocity - initial velocity upon time
acceleration= 0.2m/s sq
time= 30s
10 = displacement/time
10 = x/30
10 = 300
Answer is 300 meters - distance/displacement.
Scientists could investigate this idea by making cathode ray tubes out of different materials to see if the ray was the same.
Answer:
The series A test tube has some left amount of glucose left in it.
Explanation:
Let's assume that a fixed amount of glucose is synthesized, for the fixed quantity the bacteria produced in A and B be x and y respectively,
Therefore, the condition on x and y is, y > x as the no. of bacteria present in B is greater.
As a result B would require a greater amount of energy for its functioning, these energy would be derived from the already fixed amount of glucose present.
A test tube would also require the energy for its x number of bacteria, but it is less than that of B.
Therefore, there would be some unused glucose left in Test Tube Series A which has unused energy.
20waves/57.1s = 0.350 Hz
thank you!
