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Delvig [45]
2 years ago
9

I’ll give brainliest if it’s correct ;-;z

Physics
1 answer:
BlackZzzverrR [31]2 years ago
6 0

Explanation:

what is the question? could you pls provide it

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The first antiparticle, the positron or antielectron, was discovered in 1932. It had been predicted by Paul Dirac in 1928, thoug
Taya2010 [7]

Answer:

Energy of Photon = 4.091 MeV

Explanation:

From the conservation of energy principle, we know that total energy of the system must remain conserved. So, the energy or particles before collision must be equal to the energy of photons after collision.

K.E OF electron + Rest Energy of electron + K.E of positron + Rest Energy of positron = 2(Energy of Photon)

where,

K.E OF electron = 3.58 MeV

Rest Energy of electron = 0.511 MeV

Rest Energy of positron = 0.511 MeV

K.E OF positron = 3.58 MeV

Energy of Photon = ?

Therefore,

3.58 MeV + 0.511 MeV + 3.58 MeV + 0.511 MeV = 2(Energy of Photon)

Energy of Photon = 8.182 MeV/2

<u>Energy of Photon = 4.091 MeV</u>

8 0
3 years ago
A motorbike is travelling with a velocity of 3m/s. It accelerates at a rate of 9.3m/s for 1.8s. Calculate the distance it travel
Misha Larkins [42]

Explanation:

Consider the kinematic equation,

x  = vt +  \frac{1}{2} a {t}^{2}

where x is the distance traveled, v is the initial velocity, a is the acceleration and t is time. By plugging in known values and solving for x,

x = 3(1.8) +  \frac{1}{2} (9.3) {1.8}^{2}

through simple algebra we get

x = 20.466

where this is the distance traveled in meters.

4 0
3 years ago
Please help answer the question in the screenshot. it's multiple choice..
Talja [164]

Answer:

Since F = G * m1 * m2 / r^2

F = 6.67 * 19E-11 * 2.79 * 9.47 * 10E23 / (1.2 * 10^7)^2

F = 126 * 10E-2 N  = 1.22 N

7 0
3 years ago
When setting your schedule, it is sometimes necessary to tell people "No." Please select the best answer from the choices provid
mart [117]

Answer:

True Edg2020

Explanation:

6 0
3 years ago
Read 2 more answers
Which velocity graph shows the car moving toward the right (away from the origin) at a steady (constant) velocity? 
slega [8]

Explanation:

\text{Velocity is defined as the average displacement per unit time.}

\text{Since the car is moving at a steady velocity, the velocity does not change over time, it shows a horizontal line on the }v-t\text{ graph}

\text{Therefore, only option 2,5,8 matches this requirement.}

\text{Since the car is moving to the right, which is defined as the positive direction in this question, the velocity (}v\text{) is also positive.}

\text{Therefore, only option 5 is correct.}

6 0
3 years ago
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