Answer:
3.085 [m].
Explanation:
1) The rule:
m₁*g*l₁=m₂*g*l₂, where m₁ and l₁ - the mass and distance for the small child, m₂ and l₂ - for the big child;
2) according to the condigion l₁+l₂=5, then
3) it is possible to make up the system:
4) finally, l₁=145/47≈3.085 [m].
Answer:
the initial velocity of bullet is u = 330.335 m /s
Explanation:
given,
mass of bullet(m) = 7 g
Mass of pendulum ( M ) = 1.5- kg
The bullet emerges from the block with a speed (V) = 200 m/s
The maximum height ( h ) = 12 cm.
Let the initial speed of the bullet be ' u '
Apply, Law of conservation of momentum :
m u = ( m + M ) V ...............................(1)
Apply, Law of conservation of Energy :
...............(2)
From equation (1) and equation (2) , we have
But V = √2gh
u = 330.335 m /s
hence, the initial velocity of bullet is u = 330.335 m /s