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Arisa [49]
3 years ago
14

State Archimedes' principle.​

Physics
2 answers:
alexdok [17]3 years ago
6 0

Answer:

We know that due to upthrust ,objects tend to lose weight when immersed in liquid.

<h3><u>Archimedes</u><u> </u><u>principle</u><u> </u><u>states </u><u>that</u><u> </u><u>"</u><u> </u><u>If</u><u> </u><u>an</u><u> </u><u>object</u><u> </u><u>is</u><u> </u><u>partially </u><u>or</u><u> </u><u>complet</u><u>ely</u><u> </u><u>immersed</u><u> </u><u>in</u><u> </u><u>the </u><u>liquid</u><u>,</u><u> </u><u>the</u><u> </u><u>weight </u><u>of</u><u> </u><u>l</u><u>iquid</u><u> </u><u>displaced</u><u> </u><u>by </u><u>the </u><u>object</u><u> </u><u>is</u><u> </u><u>its</u><u> </u><u>upthrust</u><u>.</u></h3>

This law is applicable for the gaseous medium too.The weight of the displaced liquid =pgv where p is density of liquid ,g is acceleration due to gravity and v is volume of displaced liquid.

Hope this helps...

Good luck on your assignment..

Paraphin [41]3 years ago
3 0

Answer:

Archimedes Principle states that "any body completely or partially submerged in water is acted upon by an upthrust force which is equal to the magnitude of Weight of the body."

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A 10 g particle undergoes SHM with an amplitude of 2.0 mm and a maximum acceleration of magnitude 8.0 multiplied by 103 m/s2, an
Nat2105 [25]

Answer:

a)T=0.0031416s

b)v_{max}=6.283\frac{m}{s}

c) E=0.1974J

d)F=80N

e)F=40N

Explanation:

1) Important concepts

Simple harmonic motion is defined as "the motion of a mass on a spring when it is subject to the linear elastic restoring force given by Hooke's Law (F=-Kx). The motion experimented by the particle is sinusoidal in time and demonstrates a single resonant frequency".

2) Part a

The equation that describes the simple armonic motion is given by X=Acos(\omega t +\phi)    (1)

And taking the first and second derivate of the equation (1) we obtain the velocity and acceleration function respectively.

For the velocity:

\frac{dX}{dt}=v(t)=-A\omega sin(\omega t +\phi)   (2)

For the acceleration

\frac{d^2 X}{dt}=a(t)=-A\omega^2 cos(\omega t+\phi)   (3)

As we can see in equation (3) the acceleration would be maximum when the cosine term would be -1 and on this case:

A\omega^2=8x10^{3}\frac{m}{s^2}

Since we know the amplitude A=0.002m  we can solve for \omega like this:

\omega =\sqrt{\frac{8000\frac{m}{s^2}}{0.002m}}=2000\frac{rad}{s}

And we with this value we can find the period with the following formula

T=\frac{2\pi}{\omega}=\frac{2 \pi}{2000\frac{rad}{s}}=0.0031416s

3) Part b

From equation (2) we see that the maximum velocity occurs when the sine function is euqal to -1 and on this case we have that:

v_{max}=A\omega =0.002mx2000\frac{rad}{s}=4\frac{m rad}{s}=4\frac{m}{s}

4) Part c

In order to find the total mechanical energy of the oscillator we can use this formula:

E=\frac{1}{2}mv^2_{max}=\frac{1}{2}(0.01kg)(6.283\frac{m}{s})^2=0.1974J

5) Part d

When we want to find the force from the 2nd Law of Newton we know that F=ma.

At the maximum displacement we know that X=A, and in order to that happens cos(\omega t +\phi)=1, and we also know that the maximum acceleration is given by::

|\frac{d^2X}{dt^2}|=A\omega^2

So then we have that:

F=ma=mA\omega^2

And since we have everything we can find the force

F=ma=0.01Kg(0.002m)(2000\frac{rad}{s})^2 =80N

6) Part e

When the mass it's at the half of it's maximum displacement the term cos(\omega t +\phi)=1/2 and on this case the acceleration would be given by;

|\frac{d^2X}{dt^2}|=A\omega^2 cos(\omega t +\phi)=A\omega^2 \frac{1}{2}

And the force would be given by:

F=ma=\frac{1}{2}mA\omega^2

And replacing we have:

F=\frac{1}{2}(0.01Kg)(0.002m)(2000\frac{rad}{s})^2 =40N

8 0
2 years ago
A Martian leaves Mars in a spaceship that is heading to Venus. On the way, the spaceship passes earth with a speed v = 0.80c rel
hjlf

To find the relative distance from one point to another it is necessary to apply the Relativity equations.

Under the concept of relativity the distance measured from a spatial object is given by the equation

l = l_0 \sqrt{1-\frac{v^2}{c^2}}

Where

l_0= Relative length

v = Velocity of the spaceship

c = Speed of light

Replacing with our values we have that

l = l_0 \sqrt{1-\frac{v^2}{c^2}}

l = 1.2*10^{11} \sqrt{1-\frac{0.8c^2}{c^2}}

l = 1.2*10^{11} \sqrt{1-0.8^2}

l = 7.2*10^{10}m

Therefore the distance between Mars and Venus measured by the Martin is 7.2*10^{10}m

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3 years ago
A proton moving in the positive x direction with a speed of 8.9 105 m/s experiences zero magnetic force. When it moves in the po
solniwko [45]

Answer:

The magnitude of magnetic field is 1.19 T and its direction magnetic is in negative x direction.

Explanation:

Given that,

Speed of a proton, v=8.9\times 10^5\ m/s (due +x direction)

When it moves in the positive y direction it experiences a force of, F=1.7\times 10^{-13}\ N (due positive z direction)

We need to find the magnitude and direction of the magnetic field. The magnetic force is given by :

F=q(v\times B)\\\\B=\dfrac{F}{qv}\\\\B=\dfrac{1.7\times 10^{-13}}{1.6\times 10^{-19}\times 8.9\times 10^5}\\\\B=1.19\ T

For direction :

F=q(v\times B)\\\\k=(+q)(j\times B)\\\\B=-i

So, the magnitude of magnetic field is 1.19 T and its direction magnetic is in negative x direction.

4 0
3 years ago
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