Answer:
1 1/7 of a roll of yarn.
Step-by-step explanation:
<h2><u><em>
Brainlest Please!</em></u></h2>
Answer:
a) A sample size of 5615 is needed.
b) 0.012
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
The margin of error is:

99.5% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
(a) Past studies suggest that this proportion will be about 0.2. Find the sample size needed if the margin of the error of the confidence interval is to be about 0.015.
This is n for which M = 0.015.
We have that 






A sample size of 5615 is needed.
(b) Using the sample size above, when the sample is actually contacted, 12% of the sample say they are not satisfied. What is the margin of the error of the confidence interval?
Now
.
We have to find M.



The answer is w*v*1/2*6. All you did is rearrange the numbers. (moved the 6 to the other side, which does not affect anything)
Answer:
A. Obtuse B. Right C. Acute D. Acute Hope this helps :)
Answer:
C. 90 degrees
Step-by-step explanation: