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Yuri [45]
3 years ago
5

PLEASE HELP ASAP

Mathematics
1 answer:
muminat3 years ago
4 0

Answer:

Judy has a rectangular garden 9 by 22 feet. She wants to put a grass border around the garden with a uniform width on all sides. if she has enough grass seed to cover 312 square feet, how wide can the grass border be?

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Make a decision about the given claim. do not use any formal procedures and exact calculations. use only the rare event rule. ​c
AveGali [126]
You would expect that if a coin were fair the number of times heads appears would equal the number of times tails appears for a certain number of tosses. So for 20 tosses we would expect 10 and 10. However, this is a mathematical reality and not necessarily what we would see if we actually toss the coin 20 times. In fact this half and half situation becomes more and more the case if we flip the coin a large number of times (a very, very large number of times). 20 is not a very large number of times. If the coin lands heads up 11 of 20 times, it is most likely still fair and not really favoring heads. So the claim is false.

It is only in cases where we see a very high number of heads in comparison with tails (a large discrepancy between the two) that we might start to wonder if the coin is indeed fair.
7 0
4 years ago
triangle abc to triangle def and the similarity ratio to a triangle def is 4/3 if ab is 60 what is de
4vir4ik [10]
Please give me the figure so I can answer the question!!!!!!!
4 0
4 years ago
I need this awnser because if i dont do 16 lessons i fail my math class
Lemur [1.5K]

Answer:

I'd say it is:

y/x of point m equals y/x point n

Step-by-step explanation:

6 0
3 years ago
The data below represent the weight, in kilograms, of 15 containers shipped from
Nikolay [14]

Answer:

(A) Maximum = 100 kg.

(B) Lower quartile = 55 kg.

(C) Minimum = 45 kg.

(D) Upper quartile = 93 kg.

(E) Median = 81 kg.

Step-by-step explanation:

A box-plot, also known as a box and whisker plot is a method to demonstrate the distribution of a data-set based on the following 5 number summary,

  1. Minimum (shown at the bottom of the chart)
  2. First Quartile (shown by the bottom line of the box)
  3. Median (or the second quartile) (shown as a line in the center of the box)
  4. Third Quartile (shown by the top line of the box)
  5. Maximum (shown at the top of the chart).

The data provided for the weight, in kilograms, of 15 containers shipped from  a factory in one week is as follows:

S = {45, 51, 53, 55, 55, 65, 75, 81, 84, 87, 93, 93, 95, 96, 100}

The data is already arranged in ascending order.

The maximum value is:

Maximum = 100 kg.

The first quartile is the median value of the first half of the data.

The first half of the data is:

S₁ = {45, 51, 53, 55, 55, 65, 75}

The median of this data set is the middle value, i.e. 4th value.

So, the  first quartile is:

Lower quartile = 55 kg.

The minimum value is:

Minimum = 45 kg.

The third quartile is the median value of the second half of the data.

The second half of the data is:

S₂ = {84, 87, 93, 93, 95, 96, 100}

The median of this data set is the middle value, i.e. 4th value.

So, the third quartile is:

Upper quartile = 93 kg.

The The median of the data set is the middle value, i.e. the 8th value.

Median = 81 kg.

6 0
3 years ago
Find x.<br> 7x<br> 6x+1<br> 4x+6
ExtremeBDS [4]
Explanation:
7
x
+
6
x
−
5
=
4
x
+
4
13
x
−
5
=
4
x
+
4
9
x
=
9
x
=
1
5 0
2 years ago
Read 2 more answers
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