486 is what percent of 900

The function h(t) = - 16t2 + 48t + 160 can be used to model the height, in feet, of an object t

elixir [45]

Answer:

answer is c because you have to put in the 2 and get -16

8 0

3 years ago

ammar hikes 23/4 miles of nature trail in 1 hour and 15 min .How many miles of trail does ammar hike per hour? pleas help me to

telo118 [61]

23/4 miles is as much as 5 3/4 miles. We can also write it as a decimal, because 5 3/4 = 5,75 miles.

If Ammar hikes 5,75 miles in 1 1/4 hour, then we need to find out what distance does he hike in 1/4 hour (15 minutes). To do that we can just divide 5,75 by 5 (because dividing 1 1/4 by 5 will give us 1/4 we're looking for).

5,75 / 5 = 1,15

It means that in one hour Ammar hikes 5,75 - 1,15 = 4,6 miles.

We can also write it as a fraction:

4,6 = 4 6/10 = 4 3/5 = 23/5 miles

Just pick whichever form you like :)

3 0

3 years ago

Mrs white wants to crochet beach hits and baby afghans for a church fund raising bazaar. she needs 7 hours to make a hat and 4 h

Georgia [21]

She can make 5 hats and 6 afghans in 60 hours and will make $159 and have a good stock of each item or she could make 8 hats and 1 afghan in 60 hours and make $204 for the most profit.

5 0

3 years ago

Without drawing the lines, state the gradient of the lines with the following equation y=2x+4

777dan777 [17]

Answer:

gradient m is 2

Step-by-step explanation:

the equation is y=mx+c therefore m is 2.

3 0

3 years ago

PLEASE HELP!!! Two towns are 1100 miles apart. A group of hikers starts from each town and walks down the trail toward each othe

Vinvika [58]

Answer:

2.54 miles/hr

2.04 miles/hr

Step-by-step explanation:

<u>Given: </u> Distance between the two towns = 1100 miles

Difference between speeds = $\frac{1}{2}$ miles/hr

Total time when they meet = 240 hours

Let distance traveled by first group = $x$ miles.

Now, the distance traveled by second group = (1100- $x$ ) miles/hr

The relation between Speed, Time and Distance is given as:

$\text{Speed =} \dfrac{\text{Distance}}{\text{Time}}$

Let speed of first group = $S_1$

$S_1 = \dfrac{x}{240}$

Let speed of second group = $S_2$

$S_2 = \dfrac{1100-x}{240}$

As per question, $S_1$ = $S_2$ + $\frac{1}{2}$

$\dfrac{x}{240} = \dfrac{1100-x}{240} + \dfrac{1}{2}\\\Rightarrow \dfrac{x}{240} - \dfrac{1100-x}{240} = \dfrac{1}{2}\\\Rightarrow \dfrac{x-1100+x}{240} = \dfrac{1}{2}\\\Rightarrow 2x - 1100 = 120\\\Rightarrow 2x = 1220\\\Rightarrow x = 610 ft$

Now,

$S_1 = \dfrac{x}{240}$

Putting value of $x$ :

$S_1 = \dfrac{610}{240}\\\Rightarrow S_1 = 2.54\ miles/hr$

Similarly, putting value of $x$ in $S_2$ :

$S_2 = \dfrac{1100-610}{240}\\\Rightarrow S_2=\dfrac{490}{240}\\\Rightarrow S_2 = 2.04\ miles/hr$

8 0

3 years ago