Answer:
144km^3
Step-by-step explanation:
The domain represents the time traveled. It is any positive number.
What is your question? that made no sense sweet heart.
Answer:
1000 times
Step-by-step explanation:
Given:
The Sun is roughly 10^2 times as wide as the Earth.
The Star KW Sagittarii is roughly 10^5 times as wide as the Earth.
Question asked:
About how many times as wide as the Sun is KW Sagittarii?
Solution:
Let the width of the earth =
As the Sun is roughly 10^2 times as wide as the Earth, hence the width of the sun =
And as the Star KW Sagittarii is roughly 10^5 times as wide as the Earth, hence the width of the Star =
Now, to find that how many times width of the Star KW Sagittarii is as respect to the width of the Sun, we will simply divide:
Width of the Star KW Sagittarii =
Width of the Sun =
x canceled by x
Therefore, Star KW Sagittarii is 1000 times wider than Sun.
<em>First of all we calculated width of Sun in terms of width of earth and then calculated the width of the Star in terms of earth and for comparison we did simple division that showed that the Star KW Sagittarii is 1000 times wider than the Sun.</em>
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Answer:
The measure of arc SQ is 95° ⇒ (1)
Step-by-step explanation:
- The measure of any circle is 360°
- The measure of the subtended arc to an inscribed angle is twice the measure of this angle
In the given circle
∵ S lies on the circumference of the circle
∴ ∠QSR is an inscribed angle
∵ ∠QSR is subtended by arc QR
→ By using the 2nd rule above
∴ m arc QR = 2 × m∠QSR
∵ m∠QSR = 95°
∴ m arc QR = 2 × 95
∴ m arc QR = 190°
→ By using the 1st rule above
∵ m of the circle = m arc QR + m arc SQ + m arc SR
∵ m arc SR = 75° and m arc QR = 190°
→ Substitute them in the equation above
∴ 360 = 190 + m arc SQ + 75
→ Add the like term in the right side
∴ 360 = 265 + m arc QS
→ Subtract 265 from both sides
∵ 360 - 265 = 265 - 265 + m arc SQ
∴ 95° = m arc SQ
∴ The measure of arc SQ is 95°