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3 years ago

Help, I dont know how to solve for X

Mathematics

2 answers:

labwork [276]3 years ago

4 0

Answer:

i dont know

Step-by-step explanation:

sorry

notka56 [123]3 years ago

4 0

I really don’t kno either

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8 0

4 years ago

The concentration of dichlorodiphenyltrichloroethane (DDT - an infamous pesticide) in Lake Michigan has been declining exponenti

mojhsa [17]

Answer: A) $y=13e^{-0.1359t}$

B) H = 5.10

C) Yes

Step-by-step explanation: Exponential Decay function is a model that describes the reducing of an amount by a constant rate over time. Generally, it is written in the form: $y(t)=Ce^{rt}$

A) C is initial quantity, in this case, the initial concentration of DDT. To determine r, using the data given:

$y(t)=Ce^{rt}$

$2.22=13e^{13r}$

$e^{13r}=0.1708$

Using a natural logarithm property called power rule:

$13r=ln(0.1708)$

$r=\frac{ln(0.1708)}{13}$

$r=-0.1359$

The decay function for concentration of DDT through the years is $y(t)=13e^{-0.1359t}$

B) The value of H is calculated by $y=C(0.5)^{\frac{t}{H} }$

$2.22=13(0.5)^{\frac{13}{H} }$

$(0.5)^{\frac{13}{H} }=0.1708$

Again, using power rule for logarithm:

$\frac{13}{H} log(0.5)=log(0.1708)$

$\frac{13}{H} =\frac{log(0.1708)}{log(0.5)}$

$\frac{13}{H} =2.55$

H = 5.10

Constant H in the half-life formula is H=5.10

C) Using model $y(t)=13e^{-0.1359t}$ to determine concentration of DDT in 1995:

$y(24)=13e^{-0.1359.24}$

y(24) = 0.5

By 1995, the concentration of DDT is 0.5 ppm, so using this model is possible to reduce such amount and more of DDT.

8 0

3 years ago

Please answer !! Picture shown

sasho [114]

Everything outside the parabola. Point E and point A.

5 0

3 years ago

Jan 16, 3:12:20 PM Subtract 3.x2 + 8x from 9x2 + 3x – 8.

leonid [27]

Answer:

Step-by-step explanation:

ok so do this

9x² + 3x - 8 - (3x² + 8x)

distribute the negative sign

9x² + 3x - 8 - 3x² - 8x

simplify

6x² - 5x - 8

hope this helps <3

8 0

3 years ago

An SUV averages 16.5 miles per gallon. The maximum average number of miles that can be driven on a full tank of gas is 363 miles

Scilla [17]

Answer:

$g\leq 22$

Step-by-step explanation:

Let number of gallons in tank be 'g'

We know that maximum possible number of Miles per tank of fuel are 363. This is called the fuel range of the car when gas tank is full

For every gallon which is being utilized there is a decrease in range by 16.5 Miles

Hence the highest possible gallons of tank will be when the car gives full range.

Hence range is function of gallons and equation can be written as follows:

$Range (g) = 363-16.5(g) \geq 0$

Solving for g

$g \leq \frac{363}{16.5}$

$g \leq 22$

Which means that maximum possible fuel in SUV can be 22 Gallons

6 0

3 years ago

Help, I dont know how to solve for X​

Help, I dont know how to solve for X