Answer:
4477381.7 calories/pound
Explanation:
It is given that,
When a candle burns it produced 41,300 Joules per 1 gram.
We need to convert it into calories per pound.
We know that,
1 cal = 4.184 J
⇒ 1 J = (1/4.184) cal
1 pound = 453.592 grams
⇒1 g = (1/453.592) pounds
Now,
Hence, 41,300 Joules/gram = 4477381.7 calories/pound.
We are given with the equilibrium constant of acid, HF and is asked to calculate the pH of 0.30 M NaF solution. The formula to be followed is
Ka = [H+][F-]/[HF]Ka = 7.2 x 10 -4 = x^2/[0.3-x]x = [H+]= pH = -log (H+) = 1.84
Answer:
Explanation:
The electron in the lowest energy state will be found in 1 s energy level.
set of 4 possible quantum numbers
Principal quantum no : n = 1 ,
Azimuthal quantum no l = 0
Magnetic quantum no m = 0
Spin quantum no s = + 1/2
set of other quantum nos
Principal quantum no : n = 1 ,
Azimuthal quantum no l = 0
Magnetic quantum no m = 0
Spin quantum no s = - 1/2
