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3 years ago

if salt and sand is mixed with distilled water, what will be the residue? and, what will be the filtrate?

Chemistry

1 answer:

Anna35 [415]3 years ago

3 0

Answer:

Filtration is a technique used as a remedy to separate mixes

Explanation:

If you have a sodium, then you will explore that salt dissolves but the sand is still the same.

If the salt in the resin water solution scanners, the sand remains the residue and passes through the filter paper.

All you have to do now is pleasant the salty water so that the water can evaporate, leaving the salt behind.

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. Bob plants some seeds in a small cup. He puts the cup in the light and waters the soil every day. After 4 days, the seedlings

ANTONII [103]

Answer: the first option is correct

Why: the seed is the one doing all the work and no other forces were mentioned after 4 days

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3 years ago

ANSWER FAST PLZ 25 POINTS!!!!!!!!!!!!!!!

Viktor [21]

Answer:

Explanation:

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3 years ago

Find the enthalpy of neutralization of HCl and NaOH. 137 cm3 of 2.6 mol dm-3 hydrochloric acid was neutralized by 137 cm3 of 2.6

liraira [26]

Answer : The correct option is, (D) 89.39 KJ/mole

Explanation :

First we have to calculate the moles of HCl and NaOH.

$\text{Moles of HCl}=\text{Concentration of HCl}\times \text{Volume of solution}=2.6mole/L\times 0.137L=0.3562mole$

$\text{Moles of NaOH}=\text{Concentration of NaOH}\times \text{Volume of solution}=2.6mole/L\times 0.137L=0.3562mole$

The balanced chemical reaction will be,

$HCl+NaOH\rightarrow NaCl+H_2O$

From the balanced reaction we conclude that,

As, 1 mole of HCl neutralizes by 1 mole of NaOH

So, 0.3562 mole of HCl neutralizes by 0.3562 mole of NaOH

Thus, the number of neutralized moles = 0.3562 mole

Now we have to calculate the mass of water.

As we know that the density of water is 1 g/ml. So, the mass of water will be:

The volume of water = $137ml+137ml=274ml$

$\text{Mass of water}=\text{Density of water}\times \text{Volume of water}=1g/ml\times 274ml=274g$

Now we have to calculate the heat absorbed during the reaction.

$q=m\times c\times (T_{final}-T_{initial})$

where,

q = heat absorbed = ?

$c$ = specific heat of water = $4.18J/g^oC$

m = mass of water = 274 g

$T_{final}$ = final temperature of water = 325.8 K

$T_{initial}$ = initial temperature of metal = 298 K

Now put all the given values in the above formula, we get:

$q=274g\times 4.18J/g^oC\times (325.8-298)K$

$q=31839.896J=31.84KJ$

Thus, the heat released during the neutralization = -31.84 KJ

Now we have to calculate the enthalpy of neutralization.

$\Delta H=\frac{q}{n}$

where,

$\Delta H$ = enthalpy of neutralization = ?

q = heat released = -31.84 KJ

n = number of moles used in neutralization = 0.3562 mole

$\Delta H=\frac{-31.84KJ}{0.3562mole}=-89.39KJ/mole$

The negative sign indicate the heat released during the reaction.

Therefore, the enthalpy of neutralization is, 89.39 KJ/mole

3 0

4 years ago

What is the mole ratio of butane to carbon dioxide?

masha68 [24]

Butane is 2, and carbon dioxide is 8. which makes the mole ratio of butane to carbon dioxide 2:8, which simplifies to 1:4.

5 0

3 years ago

Is a animal searching for water a stimulus or response

motikmotik

Answer:

response I believe

Explanation:

i'm pretty sure it's a response cause it's the animal responding to needing water and being thirsty

hope this helps! :)

4 0

3 years ago