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Naya [18.7K]
3 years ago
6

How can two objects have the same temperature but different thermal energies?

Chemistry
1 answer:
Mamont248 [21]3 years ago
7 0
Thermal energy is dependent on the mass. If objects have a different mass then they will have a different thermal energies.
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A screw has 4 threads per centimeter and a circumference of 2 centimeters. The mechanical advantage of the screw is?
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<span>The answer is 8. Hope this help!!!

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3 years ago
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Suppose that a certain atom possesses only four distinct energy levels. Assuming that all transitions between levels are possibl
olya-2409 [2.1K]

Answer:

Following are the response to the given question:

Explanation:

The number of shells

n = 4

Calculating the spectral line:

= \frac{n(n-1)}{2}\\\\ = \frac{4(4-1)}{2} \\\\= \frac{4\times 3}{2}\\\\ = \frac{12}{2}\\\\ = 6

4 0
3 years ago
Over the years, the thermite reaction has been used for welding railroad rails, in incendiary bombs, and to ignite solid-fuel ro
melamori03 [73]

<u>Answer:</u> The mass of nickel (II) oxide and aluminium that must be used is 18.8 g and 4.54 g respectively.

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}      .....(1)

  • <u>For nickel:</u>

Given mass of nickel = 14.8 g

Molar mass of nickel = 58.7 g/mol

Putting values in equation 1, we get:

\text{Moles of nickel}=\frac{14.8g}{58.7g/mol}=0.252mol

For the given chemical reaction:

3NiO(s)+2Al(s)\rightarrow 3Ni(l)+Al_2O_3(s)

  • <u>For nickel (II) oxide:</u>

By Stoichiometry of the reaction:

3 moles of nickel are produced from 3 moles of nickel (II) oxide

So, 0.252 moles of nickel will be produced from \frac{3}{3}\times 0.252=0.252mol of nickel (II) oxide

Now, calculating the mass of nickel (II) oxide by using equation 1:

Molar mass of nickel (II) oxide = 74.7 g/mol

Moles of nickel (II) oxide = 0.252 moles

Putting values in equation 1, we get:

0.252mol=\frac{\text{Mass of nickel (II) oxide}}{74.7g/mol}\\\\\text{Mass of nickel (II) oxide}=(0.252mol\times 74.7g/mol)=18.8g

  • <u>For aluminium:</u>

By Stoichiometry of the reaction:

3 moles of nickel are produced from 2 moles of aluminium

So, 0.252 moles of nickel will be produced from \frac{2}{3}\times 0.252=0.168mol of aluminium

Now, calculating the mass of aluminium by using equation 1:

Molar mass of aluminium = 27 g/mol

Moles of aluminium = 0.168 moles

Putting values in equation 1, we get:

0.168mol=\frac{\text{Mass of aluminium}}{27g/mol}\\\\\text{Mass of aluminium}=(0.168mol\times 27g/mol)=4.54g

Hence, the mass of nickel (II) oxide and aluminium that must be used is 18.8 g and 4.54 g respectively.

4 0
3 years ago
List three factors thatinfluence the rate at whick dissolving occurs
lys-0071 [83]
1) Temperature (heat) of the solution
2) Concentration (amount) of both solvent (usually water) and solute (substance being dissolved by solvent)
3) Movement (kinetic energy) of the solution, as in shaking/stirring
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3 years ago
How many militias of 5.0 M H2SO4 (aq) stock silly toon are needed to prepare 100. Ml of 0.25 M H2SO4 (aq)
klemol [59]

Answer:

5 mL

Explanation:

As this is a problem regarding <em>dilutions</em>, we can solve it using the following formula:

  • C₁V₁=C₂V₂

Where subscript 1 refers to the initial concentration and volume, while 2 refers to the final C and V. Meaning that in this case:

  • C₁ = 5.0 M
  • V₁ = ?
  • C₂ = 0.25 M
  • V₂ = 100 mL

We <u>input the data</u>:

  • 5.0 M * V₁ = 0.25 M * 100 mL

And <u>solve for V₁</u>:

  • V₁ = 5 mL

8 0
3 years ago
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