<h3>
Answer:</h3>
0.75 moles NaOH
<h3>
Explanation:</h3>
We are given;
Volume of NaOH solution = 2.5 Liters
Molarity of NaOH = 0.300 M
We are required to calculate the moles of NaOH
We need to establish the relationship between moles, molarity and volume of a solution.
That would be;
Concentration/molarity = Moles ÷ Volume
Therefore;
Moles = Concentration × Volume
Thus;
Moles of NaOH = 0.300 moles × 2.50 L
= 0.75 moles
Therefore, the number of moles of NaOH is 0.75 moles
Answer: There are 
molecules in 63.00 g of 
Explanation:
According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number 
of particles.
To calculate the moles, we use the equation:
1 mole of contains = molecules
Thus 3.5 moles of contains = 
molecules.
There are molecules in 63.00 g of
Q=m°C<span>ΔT
=(500g) x (1 cal/g.</span>°C) x (48°C-21°C) = 13500 cal
13500 cal / 1000 = 13.5 kcal
<span>"What is the caloric value (kcal/g) of the french fries?"
13.5 kcal/ 2.5 g = 5.4 kcal/g</span>
C- continental drift<span />
To find molarity
We need no.of moles and solution in liter
Given data is in grams and ml
We have to convert it in required units
For no.of moles use formula
No.of mole=mass in gram / molar mass
Mass in gram = 29.1g
Molar mass = 160.4374g/mol calculated by adding the atomic wight of all atoms in LiClO4.3H2O
Atomic weight
Li= 6.941
Cl= 35.453
O= 15.9994
H= 1.00794
Now put it in mol equation
No.of mole = 29.1/160.4374
= 0.181mol of solute
Now convert solution in L from ml
235ml = 235/1000 = 0.235L
Now put these values in molarity formula
Molarity= 0.181/0.235
= 0.77M solution
