1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Firdavs [7]
2 years ago
12

Select the structure that corresponds

Chemistry
1 answer:
lyudmila [28]2 years ago
8 0

The structure that corresponds to the structure of pentanoic acid is both

CH₃CH₂CH₂CH₂COOH and also by the line formula as in Option B ,

Option C is the right answer.

<h3>What is Pentanoic Acid ?</h3>

Pentanoic Acid is given by the formula C₅H₁₀O₂ and a straight chain alkyl Carboxylic acid.

The structure that corresponds to the structure of pentanoic acid is both

CH₃CH₂CH₂CH₂COOH and also by the line formula as in Option B ,

Therefore Option C is the right answer.

To know more about Pentatonic Acid

brainly.com/question/16900825

#SPJ1

You might be interested in
We dissolve 93 grams of sodium sulfate (Na2SO4) in 20 grams of water. What is the percent by mass of sodium sulfate in this solu
dlinn [17]
It should be for the total solution of 93 plus 20 grams which is 113 grams so 93 divided by 113 grams comes to 82.3% sodium sulfate and this can be checked by multiplying 113 grams by 0.823 which results in 93 grams of sodium sulphate. 
4 0
3 years ago
One way to represent a model of an atom is in a drawing. What is another way to show an atomic model? ​
mamaluj [8]

I think by writing electronic configuration.

7 0
2 years ago
Please help make sure its correct thanks
Wewaii [24]

The empirical formula of metal iodide : CoI₃(Cobalt(III) Iodide)

<h3>Further explanation</h3>

13.02 g sample of Cobalt , then mol Co(MW=58.933 g/mol) :

\tt mol=\dfrac{mass}{Ar}=\\\\mol=\dfrac{13.02~g}{58.933}\\\\mol=0.221

Mass of metal iodide formed : 97.12 g, so mass of Iodine :

\tt =mass~metal~iodide-mass~Cobalt\\\\=97.12-13.02\\\\=84.1~g

Then mol iodine (MW=126.9045 g/mol) :

\tt \dfrac{84.1}{126.9045}=0.663

mol ratio of Cobalt and Iodine in the compound :

\tt 0.221\div 0.663=1\div 3

5 0
2 years ago
What is the solute when stirring salt in water until the salt disappears?
Umnica [9.8K]

Answer:

The solute is the substance being dissolved.

The solvent is the substance dissolving the solute.

Therefore, the salt is the solute and the water is the solvent.

Explanation:

The salt is the solute.

3 0
2 years ago
determine the ph of a buffer that is 0.55 M HNO2 and 0.75 M KNO2. tha value of Ka for HNO2 is 6.8*10^-4
Mariana [72]

Answer:

pH = 3.3

Explanation:

Buffer solutions minimize changes in pH when quantities of acid or base are added into the mix. The typical buffer composition is a weak electrolyte (wk acid or weak base) plus the salt of the weak electrolyte. On addition of acid or base to the buffer solution, the solution chemistry functions to remove the acid or base by reacting with the components of the buffer to shift the equilibrium of the weak electrolyte left or right to remove the excess hydronium ions or hydroxide ions is a way that results in very little change in pH of the system. One should note that buffer solutions do not prevent changes in pH but minimize changes in pH. If enough acid or base is added the buffer chemistry can be destroyed.

In this problem, the weak electrolyte is HNO₂(aq) and the salt is KNO₂(aq). In equation, the buffer solution is 0.55M HNO₂ ⇄ H⁺ + 0.75M KNO₂⁻ . The potassium ion is a spectator ion and does not enter into determination of the pH of the solution. The object is to determine the hydronium ion concentration (H⁺) and apply to the expression pH = -log[H⁺].

Solution using the I.C.E. table:

              HNO₂ ⇄    H⁺   +   KNO₂⁻

C(i)        0.55M       0M      0.75M

ΔC            -x            +x          +x

C(eq)  0.55M - x       x     0.75M + x    b/c [HNO₂] / Ka > 100, the x can be                                    

                                                             dropped giving ...

           ≅0.55M        x       ≅0.75M        

Ka = [H⁺][NO₂⁻]/[HNO₂] => [H⁺] = Ka · [HNO₂]/[NO₂⁻]

=> [H⁺] = 6.80x010⁻⁴(0.55) / (0.75) = 4.99 x 10⁻⁴M

pH = -log[H⁺] = -log(4.99 x 10⁻⁴) -(-3.3) = 3.3

Solution using the Henderson-Hasselbalch Equation:

pH = pKa + log[Base]/[Acid] = -log(Ka) + log[Base]/[Acid]

= -log(6.8 x 10⁻⁴) + log[(0.75M)/(0.55M)]

= -(-3.17) + 0.14 = 3.17 + 0.14 = 3.31 ≅ 3.3

3 0
3 years ago
Other questions:
  • What are the limitations of litmus paper and phenolphthalein indicators? Name two other indicators that can be used that do not
    13·2 answers
  • Find the number of moles of water that can be formed if you have 226 mol of hydrogen gas and 108 mol of oxygen gas.
    14·1 answer
  • You have 263 mL of liquid mercury, what is the mass of mercury that you have?
    10·1 answer
  • What method do water buffalo use to fight the lions
    7·1 answer
  • Which phrases describe space observatories?
    10·1 answer
  • What do astronomers use to calculate the age of the universe? Check all that apply. dark energy the age of rocks on Earth the ag
    14·2 answers
  • Select all the the abiotic factors that could impact a deer population.
    9·1 answer
  • Should I say sorry to a boy who was tryna steal my friends backpack as a joke and I was tryna kick his hand and I kicked his nos
    9·1 answer
  • Which of the 3 particles can never change without changing the identity of the atom?
    8·1 answer
  • Please answer this question according to the image below
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!