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KIM [24]
4 years ago
6

If a long steady rain is expected which clouds should be expected

Chemistry
1 answer:
Inessa [10]4 years ago
4 0
Nimbostratus clouds bring long steady rains
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Which processes occur during the second stage of technological design? Check all that apply.
Lena [83]
There is four stages of technological design:1. identify a problem or need.2. design a solution.3. implement, build, test the design.4. determine if the solution met the need.To design a solution is second stage of technological design.
3 0
4 years ago
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What mass of carbon monooxide must be burned to produce 175 kJ of heat under standard state condaitions?
Sphinxa [80]

Answer:

17.3124 grams

Explanation:

Given;

Amount of heat to be produced = 175 kJ

Molar mass of the carbon monoxide = 12 + 16 = 28 grams

Now,

The standard molar enthalpy of carbon monoxide = 283 kJ/mol

Thus,

To produce 175 kJ heat, number of moles of CO required will be

= Amount heat to be produced /  standard molar enthalpy of CO

or

= 175 / 283

= 0.6183

Also,

number of moles = Mass / Molar mass

therefore,

0.6183 = Mass / 28

or

Mass of the CO required = 0.6183 × 28 = 17.3124 grams

7 0
4 years ago
Covalent bonds are formed from the sharing of valence electrons.<br> • true or false
IRINA_888 [86]

Answer:

true

Explanation:

it ture because it true

3 0
3 years ago
Read 2 more answers
Is sponge cake a heterogeneous mixture
maxonik [38]

Answer:

though many may argue that cake batter is a homogeneous mixture because of its observable uniformity, we know it is heterogeneous. ... In other words, the mixture of ingredients from cake batter results in some chemical reactions here and there, but we are still left with a mixture of things that can be separated.

Explanation:

5 0
3 years ago
10. Hydrogen peroxide (H2O2: M = 34 g mol-1) is a powerful oxidising agent that is used in concentrated solution in rocket fuel
Lubov Fominskaja [6]

Answer:

The molality of solution=12.605 m

Explanation:

We are given that

Molar mass of Hydrogen peroxide, M=34 g/mol

Density of solution, \rho=1.11gcm^{-3}

30% Means mass of solute (Hydrogen peroxide)=30 g

Mass of solvent =100-30=70 g

Total mass of solution, m=100 g

Number of moles of solute=\frac{given\;mass}{molar\;mass}

Using the formula

Number of moles of hydrogen peroxide=\frac{30}{34}

Now, molality of solution

m=\frac{number\;of\;moles\;of\;solute}{mass\;of\;solvent}\times 1000

m=\frac{30}{70\times 34}\times 1000

m=12.605 m

Hence, the molality of solution=12.605 m

6 0
4 years ago
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