Whenever you can invert a function, you have that the graphs of and its inverse are reflected with respect to the line
So, given any point on the graph of , you can simply swap its coordinates to get the correspondent point on the original function
As an example, all exponential functions pass through the point , while all the logarithmic functions pass through the point
Answer:
B
Step-by-step explanation:
110 / 22 = 5 inches per picket
equation is y = 5x
8x12=__?