The equations a = n, b = 2n + 6 and c = n² - 1 are polynomials, and the expression for ab - c is n² + 6n + 1
<h3>How to determine the expression for ab - c?</h3>
The polynomials are given as:
a = n
b = 2n + 6
c = n² - 1
The expression ab - c is calculated using:
ab - c = n * (2n + 6) - (n² - 1)
Expand
ab - c = 2n² + 6n - n² + 1
Collect like terms
ab - c = 2n² - n² + 6n + 1
Evaluate
ab - c = n² + 6n + 1
Hence, the expression for ab - c is n² + 6n + 1
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26 , 8-6=2 so you do 24+6
11x+3y=103 and y=3x+1.
11x+3(3x+1)=103 -----> plug in (3x+1) for y in the first equation. You will want to distribute the 3 to the 3x+1 to get something that looks like:
11x+9x+3=103 ------> now you want to combine like terms
20x+3=103 ---> subtract 3 from both sides
20x=100 ----> divide both sides by 20
x=5
y=3(5)+1 ---> I like to plug in this to the equation that already has y isolated. 3*5 is 15, add 1 and you find that y=16.
(5, 16) will be your final answer (:
Answer:
-9
Step-by-step explanation:
