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ahrayia [7]
3 years ago
8

What is the common difference in the following arithmetic sequence? 2.8, 4.4, 6, 7.6

Mathematics
1 answer:
Volgvan3 years ago
8 0

Answer:

1.6

Step-by-step explanation:

4.4 - 2.8 = 1.6

6 - 4.4 = 1.6

7.6 - 6 = 1.6

You might be interested in
What is an equation of the line that passes through the points (-8,-6) and<br> (3, – 6)?
Maksim231197 [3]

Answer:

y=-6

Step-by-step explanation:

The y value isn't changing when the x value does. This means there is no rate of change or gradient. So in y=mx+c m=0 so we get y=c, c is always -6.

6 0
3 years ago
What are the points of discontinutity y=(x-3)/x^2-12x+27
madreJ [45]

Answer:

(3, -\frac{1}{6})

Step-by-step explanation:

We can rewrite the equation as

y = \frac{x - 3}{(x - 3)(x - 9)}

Notice that we have x - 3 in both the numerator and the denominator, so it looks like we can divide it out. However, what if x - 3 is 0? Then we would have y = \frac{0}{0 \times (x - 9)} = \frac{0}{0}, which is undefined. So although it looks like the numerator and denominator can be simplified, the resulting function we would get from simplification would not have the same behavior as this one (since such a function would be defined for x = 3, but this one is not).

A point of discontinuity refers to a particular point which is included in the simplified function, but which is not included in the original one. In this case, the point which is not included in the unsimplified function is at x = 3. In the simplified version of the function, if we plug in x = 3, we get

y = \frac{1}{((3) - 9)} = -\frac{1}{6}

So the point (3, -\frac{1}{6}) is our only point of discontinuity.

It's also important to distinguish between specific points of discontinuity and vertical asymptotes. This function also has a vertical asymptote at x = 9 (since it causes the denominator to be 0), but the difference in behavior is that in the case of the asymptote, only the denominator becomes 0 for a specific value of x

5 0
3 years ago
Read 2 more answers
Anything will help please
svp [43]

The way that I memorised how to do sin, cos, and tan is by the following: SOH, CAH, TOA

SOH = Sin is OPPOSITE / HYPOTENUSE

CAH = Cos is ADJACENT / HYPOTENUSE

TOA = Tan is OPPOSITE / ADJACENT

For example if we were to solve question 5

Sin T = 6 root 2 / 19

Cos T = 17 / 19

Tan T = 6 root 2 / 17

Repeat the steps for question 6

For the rest of the questions (7,8,9) you have to take the information given and figure out if you should us Sin, cos, or Tan. then plug the numbers in the calculator and while doing sin ^ -1, cos ^ -1, tan ^ -1

for example on question 7, to find the angle x they have given you the hypotenuse and the adjacent side so

cos x = 9 / 18

to find x plug: cos^-1 (9/18) in the calculator

8 0
2 years ago
F(x) = 2.5e-0.04x and g(x) = 1.2 + 0.2x.
Scilla [17]

f(x) - g(x)

2.5e - 0.04x - 1.2 + 0.2

0.16x + 5.59570457

7 0
3 years ago
Please help me! Given triangle ABC with A(-4,-2), B(4,4), and C(18,-8) write the equation for the line containing the perpendicu
Aleks [24]
On a phone here and no access to paper but you must first find the midpoint of AC which is the average of the coordinates. The perpendicular bisector will have a gradient that multiplies by AC's gradient to make -1. This will obviously pass through its mid point so as long as you know how to use y=mx+c you should be good.
5 0
3 years ago
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